Question

4[z + 3(Z - 1)] = 36 How do you solve this problem?

Answer 1

Answer:

4z+2(square)2z=2(square)6

Step-by-step explanation:

4((z+3(z-1)))=36

4(z^2-z+3((z-3)))=36

4(z^2-z+3z-3)=36

4((z^2+(-z+3z)-3))=36

4(z^2+2z-3)=36

4z^2+8z-12=36

4z^2+8z=24

((4(square)z^2))+(square)8z=(square)24

4z+2(square)2z=2(square)6

Answer 2

Answer:

3

Step-by-step explanation:

4[z+3(z-1)]=36

z+3(z-1)=36/4

z+3z-3=9

4z-3=9

4z=9+3

4z=12

z=12/4

z=3