Answer:
The correct answer is option C.
The mid point of the line segment.
Step-by-step explanation:
the perpendicular line segment construction twice using paper folding
we have to find the mid point of the given line segment.
We get the midpoint easily when fold the paper correctly
Therefore the correct answer is option C.
The mid point of the line segment.
Solving for x.
Since x<span> is on the right-hand side of the </span>equation<span>, switch the sides so it is on the left-hand side of the </span>equation<span>.
</span><span>0.04<span>x2</span>−8.504x+25302=c
</span>Simplify the quadratic and set<span> the right side equal to </span><span>0.
</span><span>0.04<span>x2</span>−8.504x+25302−c=0
</span>Use the standard form of the quadratic <span>(<span><span>a<span>x2</span>+bx+c</span>)</span></span><span> to find </span><span>a,</span><span>b,</span><span> and </span>c<span> for this quadratic.
</span><span>a=0.04,</span><span>b=−8.504,</span><span>c=25302−1c
</span>Use the quadratic formula<span> to find the </span>solutions<span>.
</span><span>x=<span>−b ± </span></span>√<span><span> <span><span>b2</span>−4ac /</span> </span><span>2a
</span></span>Substitute in the values of <span><span>a=0.04</span>,</span><span><span>b=−8.504</span>,</span><span> and </span><span><span>c=25302−1c</span>.
</span>x=<span>−(−8.504) ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
<span>Simplify.
</span>x=<span>8.504 ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
Simplify the section inside the radical<span>.
</span>x=<span>8.504 ± </span>√<span><span><span>−3976.001984+0.16c</span>/</span><span>2(0.04)
</span></span>
Simplify the denominator<span> of the </span>quadratic formula<span>.
</span>x=<span>8.504 ±</span>√<span><span>−3976.001984+0.16c/</span>0.08
</span>
Answer:
x=8.504 ±√−3976.001984+0.16c/0.08
Answer: The answer is 2275 and 0.
Step-by-step explanation: Given that the Capulet and Montague families love to write. Last year, each Capulet wrote 44 essays, each Montague wrote 66 essays and both families wrote 100100 essays in total. This year, each Capulet wrote 88 essays, each Montague wrote 1212 essays, and both families wrote 200200 essays in total. We are to find the number of Capulets members and Montagues members.
Let there are 'x' members in Capulet family and 'y' members in the Montague family. Then, we have
Multiplying first equation by 2 and then subtracting from the second equation, we have
So,
Thus, there are 2275 Capulets and 0 Montagues.
60/30 as a mixed # is 2/1 or 2
