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3 years ago

4[z + 3(Z - 1)] = 36 How do you solve this problem?

Mathematics

2 answers:

puteri [66]3 years ago

5 0

Answer:

4z+2(square)2z=2(square)6

Step-by-step explanation:

4((z+3(z-1)))=36

4(z^2-z+3((z-3)))=36

4(z^2-z+3z-3)=36

4((z^2+(-z+3z)-3))=36

4(z^2+2z-3)=36

4z^2+8z-12=36

4z^2+8z=24

((4(square)z^2))+(square)8z=(square)24

4z+2(square)2z=2(square)6

Klio2033 [76]3 years ago

4 0

Answer:

Step-by-step explanation:

4[z+3(z-1)]=36

z+3(z-1)=36/4

z+3z-3=9

4z-3=9

4z=9+3

4z=12

z=12/4

z=3

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