As given,
Step 1: Pick any three-digit counting number
Lets pick the number 643
Step 2: Reverse the digits of the original number.
So, reverse becomes 346
Now, it says that the difference of these two numbers has a tens digit of 9.
Lets, check:
So, its true that the difference has a tens digit of 9.
Another example:
Lets take 449
So reverse is = 944
Difference =
Here also the tens digit is 9.
So, the condition applies to all 3 digit numbers.
Answer:
Part a) The approximate years were 1998 and 2008
Part b) The graph in the attached figure
Step-by-step explanation:
Part a) we have
For
Solve the quadratic equation
we know that
The formula to solve a quadratic equation of the form is equal to
in this problem we have
so
substitute in the formula
therefore
The approximate years are
1997+11=2008
1997+1=1998
Part b)
Using a graphing tool
we have
The solution of the system of equations is the intersection point both graphs
The intersection point are (0.99,80) and (11.23,80)
see the attached figure
therefore
The solution part a) is correct
Answer: 6 on the extreme left has the place value 6000; the next 6 has the value 600; the next, 60; and the last, 6. The numeral for every whole number stands for a sum. 364 = 3 Hundreds + 6 Tens + 4 Ones. Hope this helps!
Step-by-step explanation: