There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
Answer:
104
Step-by-step explanation:
15 x 14= 210 divide by 2
105
180 - 105 = 75
15 + 14 + 75 = 104
Answer:
Option C is the right answer.
Step-by-step explanation:
Given that:
Length of diagonal = 25 inches
Length of rectangle = 9 inches
Width of rectangle will be one of the two legs of right angled triangle and the diagonal will be the hypotenuse.
Using Pythagorean theorem;

Taking square root;

Therefore,
Option C is the right answer.
Answer:
mean is 11.167 the median is 10
Step-by-step explanation:
Hope this helps
Answer:
x: 3 = 23 -15
x = 8 x 3
x = 24
Step-by-step explanation: