This is a basic addition/subtraction question. It's saying that they started at the 50 yard line. On the play, they gained 7 yards. So, we'll add 50+7 = 57.
They're at the 57 yard line at this point. On the second play they lost 10 yards (how unfortunate). Thereby, we will subtract 57-10=47.
50 yards +7 yards. -10 yards.
The answer will be that they'll be on the 47 yard line on the next play.
The Answer is 76.5, because 153/2 is 76.5
Answer:
3.83333333333
Step-by-step explanation:
Answer:
There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
is the Euler number
is the mean in the given time interval.
The problem states that:
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.
To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.
There are 5 weekdays, with a mean of 0.1 calls per day.
The weekend is 2 days long, with a mean of 0.2 calls per day.
So:

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?
This is
. So:


There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.
The expression would be:
3x
x=number of plays
Insert 4:
3(4)
=12
They would 12 yards after 4 plays if losing 3 yards every play.