Answer:
Step-by-step explanation:
Let S be the sample space, n(S) = 60
a) Let A be the event that the selected athlete uses
s less than a minute, n(A) = 59
The probability that a randomly selected athlete uses less a minute, P(A) = n(A)/n(S) = 59/60 = 0.9833
b) 1 - 0.9833 = 0.0167
c) 1 - 1 = 0
answer:
153.94cm²
Step-by-step explanation:
<3
Answer:
there is nothing just a a codding log
Step-by-step explanation:
It may help if you look your question you asked up and look were it is on math-way
Answer:
and im here for it :D
Step-by-step explanation: