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Bas_tet [7]
3 years ago
6

What is the domain of the function y=sqrt x+4

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

Domain: set of all numbers that can be inputted into a function


Since you cannot take the square root of a negative number, this means that x-4 CANNOT be negative. So it's either 0 or it's positive.

So.. x−4≥0

x−4+4≥0+4

x≥4


So this says: "Any number greater than or equal to 4 will result in x-4 being either 0 or some positive number"

So this means that the domain is


{x|x≥4}


This basically says: "the domain is the set of all numbers x such that x is greater than or equal to 4"


In interval notation, the domain is [4,∞)



The range is the set of all possible outputs. We can find the most extreme point of the range by plugging in the most extreme value for the domain

sqrt(x-4) = sqrt(4-4) = sqrt(0) = 0


So the smallest possible output is y=0, which means that the range is

{y|y≥0}


This basically says: "the range is the set of all numbers y such that y is greater than or equal to 0"

In interval notation, the range is


[0,∞)



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x^2-2(x)(2)+y^2-2(y)(3)=-8\qquad\text{add}\ 2^2\ \text{and}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2-2(x)(2)+2^2}_{(*)}+\underbrace{y^2-2(y)(3)+3^2}_{(*)}=2^2+3^2-8\\\\(x-2)^2+(y-3)^2=4+9-8\\\\(x-2)^2+(y-3)^2=5\\\\(x-2)^2+(y-3)^2=(\sqrt5)^2\\\\Answer:\\\\\boxed{center:(2,\ 3)}\\\\\boxed{radius:r=\sqrt5}

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