Answer:
$630
Step-by-step explanation:
week 1 : $336
week 2 : $294
gross pay : $630
Answer:
The length of side of largest square is 15 inches
Step-by-step explanation:
The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.
Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.
So,
<u>Area of square 1: 81 square inches</u>
![s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9](https://tex.z-dn.net/?f=s%5E2%20%3D%20A%5C%5Cs%5E2%20%3D%2081%5C%5C%5Csqrt%7Bs%5E2%7D%20%3D%20%5Csqrt%7B81%7D%5C%5Cs%20%3D%209)
<u>Perimeter of square 2: 48 inches</u>
![4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches](https://tex.z-dn.net/?f=4%2Aside%20%3D%20P%5C%5C4%2A%20side%20%3D%2048%5C%5Cside%20%3D%20%5Cfrac%7B48%7D%7B4%7D%5C%5Cside%20%3D%2012%5C%20inches)
We can see that a right angled triangle is formed.
Here
Base = 12 inches
Perpendicular = 9 inches
And the side of largest square will be hypotenuse.
Pythagoras theorem can be used to find the length.
![(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15](https://tex.z-dn.net/?f=%28H%29%5E2%20%3D%20%28P%29%5E2%2B%28B%29%5E2%5C%5CH%5E2%20%3D%20%289%29%5E2%2B%2812%29%5E2%5C%5CH%5E2%20%3D%2081%2B144%5C%5CH%5E2%20%3D%20225%5C%5C%5Csqrt%7BH%5E2%7D%20%3D%20%5Csqrt%7B225%7D%5C%5CH%20%3D%2015)
Hence,
The length of side of largest square is 15 inches
Step-by-step explanation:
2(x+4) = 12
or, 2x + 8 = 12
or, 2x = 12-8
or, 2x = 4
or, x = 4÷2
hence, x = 2
Answer:
6
Step-by-step explanation:
=
·
=
³ ·
³ = 2 x 3 = 6
Answer:
1. y = 3x - 3
2. y = -2 1/2x + 10
10/-4 = -2 1/2 is the slope
3. undefined
4. y = x - 4
5. y = x - 5
6. 6x + 2y = 4 and -3y = 9x + 12
7. -3x + y = 7, y = 3x + 1, and y =3x
8. y = 2x + 5
9. y = 1/4x - 4