Answer:
1 / We have the area of a rectangle ABCD = 8 x 16 = 128 ft²
2 / Find the area of an isosceles Δ DEF:
The base of the isosceles ΔDEF => DF = DC- FC = 16 -12 = 4 ft
So the area of Δ DEF = 1/2 (DF x EH) = 1/2 (4 x 6) = 12 ft²
3 / Area of the irregular shape = area ABCB + Area DEF = 128 + 12 = 140 ft²
Step-by-step explanation:
Radical 2 = 1.4 So 1.4 * 6 = 8.4
a^2 + b^2 = c^2
8.4^2 + 8.4^2 = square root of c
70.56 + 70.56 = 141.12 ≈ 141
Then you must find the square root of 141 which is 11.874 ≈ 11.9
Side a = 8.4
Side b = 8.4
Side c = 11.9
Since they are not like terms (not the same variables) you cannot simply so you leave it like that.✨ This applies for addition and subtraction only. It’s different with multiplication and division.✨
Rule: look at the sequence. It has the last number as 4 then 9 then for. 4 for odd numbers(odd term numbers like number 3,5 so on) so the last number of the 100 term is 9. It’s 509.
Answer: 1/5
Explanation: 8/40 simplified in half is 4/20 then 2/10 then 1/5!
