Answer:
The area is 12.56, and the circumference is 12.56.
Step-by-step explanation:
For the area,
We need to use the formula A=3.14*radius*radius
So we plug it in, and we get 3.14*2*2, which is 12.56 centimeters squared.
For circumference, we need to do,
C = 3.14*diameter
To find the diameter we need to do 2 (radius) x 2 which is 4
Plugging it in that would be 3.14 * 4 which is 12.56
So, in this case, the area is 12.56, and the circumference is also 12.56.
9514 1404 393
Answer:
not tangent
Step-by-step explanation:
The triangle has side lengths 5, 12, 14. You can compute the "form factor" for the triangle:
a^2 +b^2 -c^2 . . . . . . . . where 'c' is the longest side
= 5^2 +12^2 -14^2
= 25 +144 -196 = -27
The negative value tells you this triangle is obtuse. If AB were a tangent, it would be perpendicular to the radius—the triangle would be a right triangle.
If you compare this calculation to the Pythagorean theorem, you see that the length AB is longer than the length √(25+144) = 13 that is necessary for the triangle to be a right triangle. That means the angle at A is greater than 90°.
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<em>Additional comment</em>
This "form factor" calculation is part of the calculation you would do using the Law of Cosines to determine the largest angle. The sign of the "form factor" tells you the sign of the cosine of the angle. Angles whose cosine is negative are greater than 90°. A positive "form factor" indicates an acute triangle.
I find computing the "form factor" in this way makes interpretation of the result fairly easy. For me, it eliminates the confusion I had when the numbers of the Pythagorean theorem didn't add up. For me, it was too much work to figure whether the triangle was acute or obtuse, and I often got it wrong.
For those interested, the angle measure is arccos((a^2+b^2-c^2)/(2ab)). Here, that's arccos(-27/(2·5·12)) ≈ 103.003°.
Answer:
The absolute value of the quadratic term,
is less than 1
Step-by-step explanation:
The given function is y = (-1/2)·x² - 7
The parent function is y = x²
The vertical compression or stretching of a quadratic function is given by the value of the coefficient, <em>a</em>, of the quadratic term, x² of a quadratic function, a·x²
A quadratic function is vertically compressed if the coefficient,
< 1.
In the given function, y = (-1/2)·x² - 7, the absolute value of the coefficient of the quadratic term,
< 1, therefore, the equation, y = (-1/2)·x² - 7, will be vertically compressed compared to the parent function, y = x².
Hello! thanks for asking this question! -0.75 should be your answer. Please tell me if I was right!