Question

Derivative of g(x) = (2ra^(rx)+n)^p ?

Answer 1

The main formula of derivative
if g(x) = a^x, so g'(x) =  a^x. lna, a>0, a # 1, 
so g ' (x) = [(2ra^(rx)+n)^p] = 2r.a^(rx)+n)^p . ln a
so g ' (x) = 2r. ln a. a^(rx)+n)^p