Derivative of g(x) = (2ra^(rx)+n)^p ?

1 answer:

3 0

The main formula of derivative
if g(x) = a^x, so g'(x) = a^x. lna, a>0, a # 1,
so g ' (x) = [(2ra^(rx)+n)^p] = 2r.a^(rx)+n)^p . ln a
so g ' (x) = 2r. ln a. a^(rx)+n)^p

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