Suffocating with homework, comment a star if you can assist with four algebra homework questions. Twenty points.

Which points are on the graph of ƒ(x) = 2(0.5)^x

Slav-nsk [51]

x y=2*(0.5)^x

-10 2048 
-9 1024
 -8 512 
-7 256 
-6 128
 -5 64
 -4 32 
-3 16
-2 8 
-1 4 
0 2 
1 1 
2 0.5 
3 0.25
 4 0.125 
5 0.0625 
6 0.03125 
7 0.015625
 8 0.0078125 
9 0.00390625
 10 0.00195313

As x goes to negative infinity the function grows to infinity.

As x grows to infinity the function decreases an approximate to zero.

5 0

3 years ago

Rewrite the equation by completing the square. x^2 -4x =0

olasank [31]

Step-by-step explanation:

x² − 4x = 0

To complete the square, take half of the second coefficient, square it, then add the result to both sides.

(-4/2)² = 4

x² − 4x + 4 = 4

(x − 2)² = 4

x − 2 = ±2

x = 2 ± 2

x = 0 or 4

6 0

2 years ago

Josh has a rewards card for a movie theater. - He receives 15 points for becoming a rewards card holder. - He earns 3.5 points f

jeka94

Answer:

Option A. 3.5x + 15 ≥ 55

Step-by-step explanation:

Points Rosh received for becoming a member = 15

Points Rosh received for visiting the moving theater = 3.5

Total points needed for a free movie ticket = 55

For each visit he receives 3.5 points, so for x visits he will receive 3.5x points.

Total points = Points received on becoming a member + Points received on x visits

So,

Total Points = 15 + 3.5x

These points must be at least 55 for a free movie ticket. At least means equal to or greater than. So the total points must be equal to or greater than 55 in order to earn a free movie ticket. This can be expressed as:

3.5x + 15 ≥ 55

So, option A gives the correct answer

8 0

2 years ago

Read 2 more answers

Astronomy: At is closest approach, Mars is about 5.6X10^7 km from Earth and its apparent size is about 0.00012 radians. What is

Mariana [72]

1.) D = 2pi * d * A / 360 degrees; Where:
pi = 3.14;
d = distance or 56,000,000 km (5.6x10^7 to standard notation)
A = angular size in degrees or .00688 degrees (.00012 radian to degrees)

D = 2(3.14) * 56,000,000 * .00688 / 360
= 6.28 * 385,280 / 360
= 2,419,558.4 / 360
D = 6,720.996 or 6,721

Therefore, 6,721 km. is the approximate diameter of Mars.

6 0

2 years ago

Read 2 more answers

Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.

larisa86 [58]

Answer:

a) $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

b) $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

c) $t_{\alpha/2}=-2.11$

d) $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is $\alpha=1-0.87=0.13$ and $\alpha/2 =0.065$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.065$ and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values $z_{\alpha/2}=-1.51$ and $z_{\alpha/2}=1.51$

Part b

On this case the confidence is 92% or 0.92 so the significance level is $\alpha=1-0.92=0.08$ and $\alpha/2 =0.04$ . On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

$df=n-1=15-1=14$

We need values b,c on the t distribution with 14 degrees of freddom such that:

$P(t_{(14)}$ or $P(t_{(14)}>c)=0.04$ and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values $t_{\alpha/2}=-1.89$ and $t_{\alpha/2}=1.89$

Part c

The significance level is $\alpha=0.025$ and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

$df=n-1=18-1=17$

We need a value c on the t distribution with 17 degrees of freddom such that:

$P(t_{(17)}$ , and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values $t_{\alpha/2}=-2.11$

Part d

The significance level is $\alpha=0.08$ and $\alpha/2 =0.04$ . On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

$P(Z$ or $P(Z>b)=0.04$ and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values $z_{\alpha/2}=-1.75$ and $z_{\alpha/2}=1.75$

6 0

2 years ago