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Nikolay [14]
3 years ago
8

Plz prove this for me.....

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

I've answered your other question as well.

Step-by-step explanation:

Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.

Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3

⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab

Substituting a=sin2(x) and b=cos2(x), we have:

sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)

Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:

sin6(x)+cos6(x)=1−3sin2(x)cos2(x)

From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)

Meaning the expression can be rewritten as:

sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)

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If (he)={(0,1),(2,3),(-4,1)}, find h^-1(x)
ololo11 [35]

The given function is

h(x) = \{ (0,1), (2,3), (-4, 1) \}

The inverse function is

h^{-1}(x) = \{ (1,0), (3,2), (1,-4)\}

To get the inverse, we swap each x and y coordinate.

The rule is (x,y) \to (y,x)

So that's why the point (0,1) becomes (1,0) for instance.

3 0
3 years ago
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Keith_Richards [23]
Oh you can use photo math for This
5 0
3 years ago
!!Giving 15 points and brainliest!!Based on the results of the second simulation, what is the experimental probability that a gr
iragen [17]

Answer:

There's a 39% chance.

Step-by-step explanation:

7 0
3 years ago
How can you find the whole when you know part and the percent.
Usimov [2.4K]

An example should make this clear.

If  $50  is 40%   what is the value of the whole amount?

Answer:-  Whole amount = 100^%

By proportion this =  (100/ 40) * 50

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4 0
4 years ago
Find all the zeros of the function <br> g(x)=x^3-4x^2-x+22
vagabundo [1.1K]

Answer:

x = -2, x = 3 − i√8, and x = 3 + i√8

Step-by-step explanation:

g(x) = x³ − 4x² − x + 22

This is a cubic equation, so it must have either 1 or 3 real roots.

Using rational root theorem, we can check if any of those real roots are rational.  Possible rational roots are ±1, ±2, ±11, and ±22.

g(-1) = 18

g(1) = 18

g(-2) = 0

g(2) = 12

g(-11) = 1782

g(11) = 858

g(-22) = -12540

g(22) = 8712

We know -2 is a root.  The other two roots are irrational.  To find them, we must find the other factor of g(x).  We can do this using long division, or we can factor using grouping.

g(x) = x³ − 4x² − 12x + 11x + 22

g(x) = x (x² − 4x − 12) + 11 (x + 2)

g(x) = x (x − 6) (x + 2) + 11 (x + 2)

g(x) = (x (x − 6) + 11) (x + 2)

g(x) = (x² − 6x + 11) (x + 2)

x² − 6x + 11 = 0

Quadratic formula:

x = [ 6 ± √(36 − 4(1)(11)) ] / 2

x = (6 ± 2i√8) / 2

x = 3 ± i√8

The three roots are x = -2, x = 3 − i√8, and x = 3 + i√8.

5 0
3 years ago
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