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e-lub [12.9K]
3 years ago
5

F(x) = 3x + 4; Find f(3)

Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0

f(x)=3x+4 \\f(3)=3\cdot3+4 \\f(3)=9+4=\boxed{13}

Hope this helps.

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One number is 6 more than another number, and their sum is 22. find the numbers.
Artist 52 [7]
Set the smaller one to x.  2x+6=22, so 2x=16.  Thus, x=8 and x+6=14, so 8 and 14 are our numbers.
7 0
3 years ago
What is the expected value of X?
Nikitich [7]

Answer:678

Step-by-step explanation:im dumb

4 0
3 years ago
For what values of the variables are the following expressions defined? 1. 5y+2 2. 18/y 3. 1/x+7 4. 2b/10−b Example: X>7
Serga [27]

Answer:

1. All real numbers

2. All real numbers except y = 0

3. All real numbers except x = -7

4. All real numbers except b = 10

Step-by-step explanation:

For any function to be defined at a particular value, it should not be <em>approaching to a value </em>\infty<em> or it should not give us the </em>\frac{0}{0}<em> (zero by zero) form </em> when the input is given to the function.

The value of function will depend on the denominator.

Now, let us consider the given functions one by one:

1. 5y+2

Here denominator is 1. So, it can not attain a value \infty or \frac{0}{0}<em> (zero by zero) form </em>

So, for all real numbers, the function is defined.

2.\ \dfrac{18}{y}

At y = 0, the value

At\ y =0,  \dfrac{18}{y} \rightarrow \infty

So, the given function is <em>defined for all real numbers except y = 0</em>

<em></em>

<em></em>3.\ \dfrac{1}{x+7}<em></em>

Let us consider denominator:

x + 7 can be zero at a value x = -7

At\ x =-7,  \dfrac{1}{x+7} \rightarrow \infty

So, the given function is <em>defined for all real numbers except x = -7</em>

<em></em>

4.\ \dfrac{2b}{10-b}

Let us consider denominator:

10-b can be zero at a value b = 10

At\ b =10,  \dfrac{2b}{10-b} \rightarrow \infty

So, the given function is <em>defined for all real numbers except b = 10</em>

<em></em>

7 0
3 years ago
Which of the following is the solution
stealth61 [152]

|x|-2\leq -3

so|x|\leq -1 (this is wrong because |x|\geq 0 )


6 0
2 years ago
1/2 - [-1/4+2/3] how do you solve this value of the expression
Shkiper50 [21]

Answer:

1/12

Step-by-step explanation:

1/2-[-1/4+2/3]

1/2-[-3/12+8/12]

1/2-[5/12]

1/2-5/12

6/12-5/12

1/12

3 0
3 years ago
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