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bogdanovich [222]
3 years ago
5

Prove that P(2,3), (3, 4), R(5, 6) and S(4,5) are thevertices of a rhombus​

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given coordinates to us are ,

  • P(2,3) .
  • Q(3,4).
  • R(5,6)
  • S(4,5)

Here it is asked to Prove that these are vertices of Rhombus . So we know that all sides of a Rhombus are equal .So if we show that value of all sides lenght are equal , then it will be a Rhombus .

We will use Distance Formula .

Now , here ,

<u>Dista</u><u>nce</u><u> </u><u>betwe</u><u>en</u><u> </u><u>P</u><u> </u><u>and</u><u> </u><u>Q</u><u> </u><u>:</u>

⇒ x = √ (2 - 3)² + (3-4)² .

⇒ x = √ (-1)² + (-1)² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

<u>Dista</u><u>nce</u><u> </u><u>betwee</u><u>n</u><u> </u><u>Q</u><u> </u><u>and</u><u> </u><u>S</u><u> </u><u>:</u>

⇒ x =√ [ (3-4)² + (5-4)².

⇒x = √ 1² + 1² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Similarly we can prove other distances equal.

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