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Ierofanga [76]
3 years ago
13

At the beginning of the year, Young Company bought three used machines from Vince, Inc. The machines immediately were overhauled

, were installed, and started operating. Because the machines were different, each was recorded separately in the accounts. Machine A Machine B Machine C Amount paid for asset $ 8,250 $ 26,900 $ 10,600 Installation costs 250 650 550 Renovation costs prior to use 2,800 1,350 1,750 Repairs after production began 530 480 650 By the end of the first year, each machine had been operating 9,000 hours. Required: Compute the cost of each machine. Prepare the journal entry to record depreciation expense at the end of year 1, assuming the following: TIP: Remember that the formula for double-declining-balance uses cost minus accumulated depreciation (not residual value). Estimates Machine Life Residual Value Depreciation Method A 5 years $ 200 Straight-line B 50,000 hours 1,000 Units-of-production C 6 years 2,400 Double-declining-balance
Business
1 answer:
neonofarm [45]3 years ago
8 0

Answer and Explanation:

a. The computation of cost of machine is shown below:-

                                                          Machine A   Machine B       Machine C

Amount paid for Assets                   $8,250          $26,900          $10,600

Add: Installation Cost                       $250             $650               $550

Add: Renovation Cost prior to use  $2,800         $1,350             $1,750

Total Cost                                          $11,300         $28,900          $12,900

b. To record the depreciation expense at the end of year 1 is shown below:-

Depreciation expense Dr, $11,402

     To Accumulated Depreciation-Machine A $2,080

     To Accumulated depreciation-Machine B $5,022

     To  Accumulated Depreciation-Machine C $4,300

(Being depreciation expenses is recorded)

Working note

For Machine A

Depreciable amount = Cost of Assets - Salvage Value

= $10,600 - $200

= $10,400

Depreciation expenses = Depreciable amount ÷ Life

= $10,400 ÷ 5

= $2,080

For Machine B

Depreciable amount = Cost of Assets - Salvage Value

= $28,900 - 1,000

= $27,900

Depreciation rate per hour = Depreciation expenses = Depreciable amount ÷ Life

= $27,900 ÷ 50,000

= 0.558

Depreciation expense = Depreciation rate per hour × Number of hours worked

= 0.558 × 9,000

= $5,022

For Machine C

Rate of double declining method = 1 ÷ 6 × 2

= 33.33%

Depreciation expense = Cost of assets × Rate of double declining method

= $12,900 × 33.33%

= $4,300

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6 0
3 years ago
Grainger Company is a major automotive parts manufacturer operating in six countries. It has no restrictions on stock sales and
alisha [4.7K]

Answer:

The correct word for the blank space is: public.

Explanation:

A public corporation has sold stock through an<em> Initial Public Offering </em>(IPO) to the public and that stock is currently traded on a <em>public stock exchange</em> or the <em>Over-The-Counter</em> (OTC) market. The ability to sell public shares is very important to these businesses as it provides them with a source of capital for investment.

5 0
3 years ago
Consider a city of 200 people (100 rich and 100 poor) and two neighborhoods (100 people in each). Both groups generally prefer t
Mekhanik [1.2K]

Answer:

Explanation:

Step 1. Given information.

  • City of 200 people
  • 100 rich, 100 poor.

Step 2. Formulas needed to solve the exercise.

  • P(poor) = 0.9x^2
  • P(rich)= 35x-0.1x^2

Step 3. Calculation and step 4. Solution.

P(poor) = p (rich)

0.9x2 = 35x - 0.1x2

1x2 = 35x

x = 35

x is the percentage of rich above 50%, thus there are 35% rich people above 50%.

P (poor) = 1102.5

P (rich) = 1102.5

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3 0
4 years ago
The McDonald's fast-food restaurant on campus sells an average of 4,000 quarter-pound hamburgers each week. Hamburger patties ar
san4es73 [151]

Answer: 11.42 times

Explanation:

Inventory Turnover = Cost of Goods Sold / Average inventory

Where,

Cost of goods sold = 4,000 quarter-pound hamburgers each week x $1.00 a pound

COGS = $4,000 per week

Average Inventory = 350 pounds of hamburger

Inventory Turnover = 4000 / 350 = 11.42 times

3 0
3 years ago
The function y= -6(x - 5)2 + 12 shows the daily profit (in hundreds of
tino4ka555 [31]

Answer:

D. Interpretation: The zeros are where the daily profit is $0.00

zeros: x = 3.586 and x = 6.414

Explanation:

We have been given the following daily profit function;

y=-6(x-5)^{2}+12

where y is the profit (in hundreds of  dollars) of a taco food truck

and x the price of a taco (in dollars)

The zeros of this profit function can be obtained by solving for x in the following equation;

0=-6(x-5)^{2}+12

These will simply be the x-intercepts of the profit function. That is the points where the profit function crosses or intersects the x-axis.

Therefore, an interpretation of the zeros of this function would be;

The zeros are where the daily profit is $0.00

These zeros can be evaluated graphically. We first obtain the graph of the profit function as shown in the attachment below;

We then determine the x values where the graph crosses the x-axis. These values will represent the zeros of our profit function. From the graph, these points are;

x = 3.586 and x = 6.414

8 0
3 years ago
Read 2 more answers
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