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Ierofanga [76]
2 years ago
13

At the beginning of the year, Young Company bought three used machines from Vince, Inc. The machines immediately were overhauled

, were installed, and started operating. Because the machines were different, each was recorded separately in the accounts. Machine A Machine B Machine C Amount paid for asset $ 8,250 $ 26,900 $ 10,600 Installation costs 250 650 550 Renovation costs prior to use 2,800 1,350 1,750 Repairs after production began 530 480 650 By the end of the first year, each machine had been operating 9,000 hours. Required: Compute the cost of each machine. Prepare the journal entry to record depreciation expense at the end of year 1, assuming the following: TIP: Remember that the formula for double-declining-balance uses cost minus accumulated depreciation (not residual value). Estimates Machine Life Residual Value Depreciation Method A 5 years $ 200 Straight-line B 50,000 hours 1,000 Units-of-production C 6 years 2,400 Double-declining-balance
Business
1 answer:
neonofarm [45]2 years ago
8 0

Answer and Explanation:

a. The computation of cost of machine is shown below:-

                                                          Machine A   Machine B       Machine C

Amount paid for Assets                   $8,250          $26,900          $10,600

Add: Installation Cost                       $250             $650               $550

Add: Renovation Cost prior to use  $2,800         $1,350             $1,750

Total Cost                                          $11,300         $28,900          $12,900

b. To record the depreciation expense at the end of year 1 is shown below:-

Depreciation expense Dr, $11,402

     To Accumulated Depreciation-Machine A $2,080

     To Accumulated depreciation-Machine B $5,022

     To  Accumulated Depreciation-Machine C $4,300

(Being depreciation expenses is recorded)

Working note

For Machine A

Depreciable amount = Cost of Assets - Salvage Value

= $10,600 - $200

= $10,400

Depreciation expenses = Depreciable amount ÷ Life

= $10,400 ÷ 5

= $2,080

For Machine B

Depreciable amount = Cost of Assets - Salvage Value

= $28,900 - 1,000

= $27,900

Depreciation rate per hour = Depreciation expenses = Depreciable amount ÷ Life

= $27,900 ÷ 50,000

= 0.558

Depreciation expense = Depreciation rate per hour × Number of hours worked

= 0.558 × 9,000

= $5,022

For Machine C

Rate of double declining method = 1 ÷ 6 × 2

= 33.33%

Depreciation expense = Cost of assets × Rate of double declining method

= $12,900 × 33.33%

= $4,300

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Altoon Manufacturing's records were partially destroyed in a flood. The company does not know what sales have been for the year,
Masteriza [31]

Answer:

a. $164,000

Explanation:

The computation of the Altoon Manufacturing's sales for the year until the flood is given below:

= Cash collections + ending receivables - opening receivables

= $158,000 + $25,000 - $19,000

= $164,000

hence, the Altoon Manufacturing's sales for the year until the flood is $164,000

Therefore the first option is correct

7 0
2 years ago
A corporation makes an investment of $20,000 that will provide the following cash flows after the corresponding amounts of time:
s344n2d4d5 [400]

A) The company should not invest in the provided project due to the negative NPV of the project.

B) The NPV of the project comes out to be (286).

<h3>What is NPV?</h3>

NPV is an abbreviated form of Net present value and computed by deducting the cash outflows from cash inflows at the present value.

Given values:

Cash flow of year 1: $10,000

Cash flow of year 2: $10,000

Cash flow of year 3: $2,000

Cash outflow (cost of investment) =$20,000

Step-1 Computation of PV of cash inflows of every year:

PV of year 1 = Cash inflow of year 1 / (1+ interest rate)^ 1

                    = $10,000 / (1+0.07) ^ 1

                    = $10,000 X 0.934579

                    = $9,346

PV of year 2 = Cash inflow of year 1 / (1+ interest rate)^ 2

                    = $10,000 / (1+0.07) ^ 2

                    = $10,000 X 0.873438

                    = $8,735

PV of year 3= Cash inflow of year 1 / (1+ interest rate)^ 3

                   = $2,000 / (1+0.07) ^ 2

                    = $2,000 X 0.816297

                    =$1,633

Step-2 Computation of total amount of PV of cash inflows:

\rm\ PV \rm\ of \rm\ cash \rm\ inflows = \rm\ PV \rm\  of \rm\  year \rm\  1 + \rm\  PV \rm\ of \rm\ year \rm\ 2 + \rm\ PV \rm\ of \rm\ year \rm\ 3\\\rm\ PV \rm\ of \rm\ cash \rm\ inflows =\$9,346 + \$8,735 + \$1,633\\\rm\ PV \rm\ of \rm\ cash \rm\ inflows =\$19,714

Step-3 Computation of NPV:

\rm\ NPV=\rm\ PV \rm\ of \rm\ cash \rm\ inflows- \rm\ Cost \rm\ of \rm\ investment\\\rm\ NPV=\$19,714-\$20,000\\\rm\ NPV=\$ (286)

Therefore, the NPV comes out to be a negative amount of 286, and hence, the company should not accept the project.

Learn more about the net present value in the related link:

brainly.com/question/14015430

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5 0
2 years ago
Mary makes 10 pies and 20 cakes a day and her opportunity cost of producing a cake is 2 pies. Tim makes 20 pies and 10 cakes a d
monitta

Answer:

If Mary and Tim specialize in the good in which they have a comparative​ advantage, ______.

Mary would specialize in making cakes while Tim would specialize in making pies.

Explanation:

a) Data and Calculations:

Mary's opportunity cost of making a cake = 2 pies

She can make additional 5 (10/2) cakes instead of making pies

This will increase her cakes to 25 a day (20 + 5)

Tim's opportunity cost of making a cake = 4 pies

She can make additional 40 pies (10 * 4) instead of making cakes

This will increase her pies to 60 pies a day (20 + 40)

When they specialize there will be 25 cakes and 60 pies produced in a day instead of 30 cakes and 30 pies.

5 0
3 years ago
George bought a car for $26,500. he made no down-payment and financed the entire amount on a 5-year term with a monthly payment
pentagon [3]
Given:
Principal, P = 26500
term=5 years
Monthly payment, A = 695

Question: Find interest rate

Solution:
Unless there is a table available, there is no explicit formula to calculate interest.  However, the interest rate can be solved for using the formula to calculate the monthly payment, as follows.

A=\frac{P(i*(1+i)^{n})}{(1+i)^{n}-1}
Substituting 
P=26500
i=monthly interest rate to be found
A=monthly payment=695
n=5*12=60 months
A=\frac{26500(i*(1+i)^{60})}{(1+i)^{60}-1}
Rearrange to give successive estimates of i by
I(i)=(695/26500)*((1+i)^60-1)/(1+i)^60
Try initial estimate of i=0.02  (2% per month)
I(0.02)=0.0182
I(0.0182)=0.01736
I(0.01736)=0.01689
....
Eventually we get the value to stabilize at i=0.016265, or
Monthly interest = 1.6265% (to four decimal places)


4 0
2 years ago
_____ is a process that helps organizations identify, select, organize, disseminate, transfer, and apply expertise that are part
Drupady [299]
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3 0
3 years ago
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