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True [87]
3 years ago
7

A rectangle has an area of 45x2 − 42x − 48 and a width of 5x − 8. What is the length of the rectangle?

Mathematics
2 answers:
kvv77 [185]3 years ago
8 0

Answer:

3(3x+2)=9x+6 units.

Step-by-step explanation:

We have been given that a rectangle has an area of 45x^2-42x-48 and a width of 5x-8. We are asked to find the length of the rectangle.

Since we know that area of a rectangle equals to the product of its width and length, so to find the length of our given rectangle we will divide area of the rectangle by its width.

\text{Length of rectangle}=\frac{45x^2-42x-48}{5x-8}

\text{Length of rectangle}=\frac{3(15x^2-14x-16)}{5x-8}        

\text{Length of rectangle}=\frac{3(15x^2+10x-24x-16)}{5x-8}

\text{Length of rectangle}=\frac{3(5x(3x+2)-8(3x+2))}{5x-8}  

\text{Length of rectangle}=\frac{3((3x+2)(5x-8))}{5x-8}  

Upon cancelling 5x-8 from numerator and denominator we will get,

\text{Length of rectangle}=3(3x+2)  

\text{Length of rectangle}=9x+6  

Therefore, the length of the rectangle is 3(3x+2)=9x+6 units.

Irina18 [472]3 years ago
3 0

Dividend

Divisor

and

9x+6

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