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elena-s [515]
4 years ago
6

(Distribute , then simplify the remaining expression. Final answer must be in standard form) Please help !!

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
8 0
Problem 22
4x^2(2x^2+x-5) - x(x^3+5x^2-3) + 17
4x^2(2x^2)+4x^2(x)+4x^2(-5) - x(x^3)-x(5x^2)-x(-3) + 17
8x^4+4x^3-20x^2 - x^4-5x^3+3x + 17
7x^4-x^3-20x^2+3x + 17

So the final simplified answer to problem 22 is
7x^4-x^3-20x^2+3x + 17

--------------------------------

Problem 23
-2x(x^3-6x^2+6)+4x^3-(5x^4+10x)
-2x(x^3)-2x(-6x^2)-2x(6)+4x^3-(5x^4)-(10x)
-2x^4+12x^3-12x+4x^3-5x^4-10x
-7x^4+16x^3-22x

So problem 23 simplifies to
-7x^4+16x^3-22x

---------------------------------------------------------

Problem 24
4b[2a^2-5(3ab-2b^2)]+29ab^2
4b[2a^2-5(3ab)-5(-2b^2)]+29ab^2
4b[2a^2-15ab+10b^2]+29ab^2
4b[2a^2]+4b[-15ab]+4b[10b^2]+29ab^2
8a^2b-60ab^2+40b^3+29ab^2
8a^2b-31ab^2+40b^3

So problem 24 simplifies to 
8a^2b-31ab^2+40b^3

-------------------------------------------------

Problem 25
2y(6x-4x^2y)+13x^2y^2-6
2y(6x)+2y(-4x^2y)+13x^2y^2-6
12xy-8x^2y^2+13x^2y^2-6
12xy+5x^2y^2-6

The final answer for problem 25 is
12xy+5x^2y^2-6
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In a shopping mall, 5/8 of the shoppers were female shoppers at first. A short
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Answer:

104

Step-by-step explanation:

5/8x. - - - - - - - >. 3/8x

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Then solve for x

8 0
3 years ago
The ages of four sisters are consecutive even integers. Two times the age of the youngest sister exceeds the oldest sister's age
S_A_V [24]

Alright, lets get started.

The ages of all four sisters will be = x, x+2, x+4, x+6

As per given in question, two times of youngest sister age exceeds the oldest sister age by 30 means

2x - 30 = (x+6)

Simplifying the equation

2x - (x+6) = 30

2x - x - 6 = 30

x = 36

So this is the age of youngest sister.

So, age of oldest sister will be x + 6 = 36 + 6 = 42

Hene the age of oldest sister is 42 years.   :  Answer

Hope it will help :)


5 0
3 years ago
Read 2 more answers
Who wants to be friends??????
maw [93]
Hello!

Since y is equal to both of them they are equal to each other

3x + 7 = 3x + 2

Now you solve it algebraically

Subtract 2 from both sides

3x + 5 = 3x

Subtract 3x from both sides

5 = 0

Since 5 does not equal 0 there are no solutions

The answer is D

Hope this helps!
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6 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided
VashaNatasha [74]

Answer: x = -4, x = 5

Step-by-step explanation:

You can use the substitution method for this problem.

y = x^{2} + 2x, but y also = 3x +20.

Because of this, you can determine that x^{2} +2x = 3x + 20 because they are both equal to the same thing, y.

Solve the quadratic equation you got from substitution:

x^{2} + 2x = 3x + 20

x^{2} -x = 20

x^{2} -x -20 = 0

You can factor this equation:

(x+4)(x-5) = 0

x = -4, x = 5

5 0
3 years ago
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