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Olegator [25]
4 years ago
15

What is the solution to the equation m+ 3-3-m

Mathematics
1 answer:
Crazy boy [7]4 years ago
7 0

Step-by-step explanation:

No solution because m is subtracted by m and 3 by 3 so no solution

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According to the graph, what is the value of the constant in the equation
lilavasa [31]
The answer to your question is C.48
3 0
3 years ago
Plz help!
zloy xaker [14]
The factored expression is: 3(5n-6)
The GCF between 15 and 18 is 3. So you would divide both numbers by 3. That would leave you with 5 taking the place of 15 and 6 taking the place of 18. Then you would fill in the blanks. Three multiplied by the expression 5n-6 would give you your original expression of 15n-18.
8 0
4 years ago
TEST!!!<br> Help my teacher never teach us.<br> Geometry
Reil [10]

Answer:

z=27

x=114

Step-by-step explanation:

6z-96 = 66

6z=162

z=27

180-x=66

x=114

6 0
4 years ago
Use f’( x ) = lim With h ---&gt; 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}

Hence, on putting the value in the formula:

f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

      Hence, the derivative of the function f(x) is:

          f'(x)=-2x

3 0
3 years ago
Read 2 more answers
How does one solve for the n+1st term with the nth term of a sequence
love history [14]

Answer:

<h3>The answer is option B</h3>

Step-by-step explanation:

The nth term of the sequence is

A(n) = 5n + 7

To find the (n+1)st term substitute n+1 into the general equation

That's

<u>For (n + 1)st term</u>

A(n+1) = 5(n+ 1) + 7

A(n+1) = 5n + 5 + 7

<h3>A(n+1) = 5n + 12</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
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