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AveGali [126]
3 years ago
5

1/3 / 1/2 in a fraction form

Mathematics
1 answer:
ratelena [41]3 years ago
7 0

Answer:

Step-by-step explanation:

2/4 5/6

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Let f(x) = 27x5 − 33x4 − 21x3 and g(x) = 3x2. Find f of x over g of x
r-ruslan [8.4K]
I am assuming when you write 27x5 u mean "27 times x to the power of 5".

therefore, your answer is 9x3-11x2-7x
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Lamont has a lawn care business. For each lawn that he mows, he charges a supply
yawa3891 [41]

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D. $9.50

Step-by-step explanation:

If you take the $155 and subtract the $15 per lawn mowed you get $95. If then you add up the total hours he spent mowing (10) and divide the $155 by the 10 you end up with $9.50 for each hour he spent mowing.

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PLZ HELP!! NEED QUICKLY!!<br> Fill In The Blanks!!
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Answer:

Step-by-step explanation:

Statement                                   Solution

1. AB = CB                                  Definition of isosceles triangle

2: AD = DC                                  BD is the median to base AC

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4 years ago
3-4x-2
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_

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d

d

d

_

d(

d

_d_d

ddi(

d

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Step-by-step explanation:

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8 0
2 years ago
Need help #3. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Sunny_sXe [5.5K]

Answer:

A

Step-by-step explanation:

We are given a right triangle with a base of <em>x</em> feet and a height of <em>h</em> feet, where <em>x</em> is constant and <em>h</em> changes with respect to time <em>t</em>.

The angle in radians is defined by:

\displaystyle \tan(\theta)=\frac{h}{x}

And we want to find the relationship that describes dθ/dt and dh/dt.

So, we will differentiate both sides with respect to <em>t</em> where <em>x</em> is a constant:

\displaystyle \frac{d}{dt}[\tan(\theta)]=\frac{d}{dt}\Big[\frac{h}{x}\Big]

Differentiate. Apply the chain rule on the left. Again, remember that <em>x</em> is just a constant, so we can move it outside the derivative operator. Therefore:

\displaystyle \sec^2(\theta)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

Since we know that tan(θ)=h/x, <em>h</em> is the opposite side of our triangle and <em>x</em> is the adjacent. Therefore, by the Pythagorean Theorem, our hypotenuse will be:

\text{Hypotenuse}=\sqrt{h^2+x^2}

Since secant is the ratio of the hypotenuse to adjacent:

\displaystyle \sec(\theta)=\frac{\sqrt{h^2+x^2}}{x}

So:

\displaystyle \sec^2(\theta)=\frac{x^2+h^2}{x^2}

By substitution, we have:

\displaystyle \Big(\frac{x^2+h^2}{x^2}\Big)\frac{d\theta}{dt}=\frac{1}{x}\frac{dh}{dt}

By multiplying both sides by the reciprocal of the term on the left:

\displaystyle \frac{d\theta}{dt}=\frac{1}{x}\Big(\frac{x^2}{x^2+h^2}\Big)\frac{dh}{dt}

Therefore:

\displaystyle \frac{d\theta}{dt}=\frac{x}{x^2+h^2}\frac{dh}{dt}

Our answer is A.

3 0
3 years ago
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