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Simora [160]
3 years ago
5

cSuppose you are standing such that a 45-foot tree is directly between you and the sun. If you are standing 200 feet away from t

he tree and the tree casts a 225-foot shadow, how tall could you be and still be completely in the shadow of the tree? x 225 ft 200 ft 45 ft Your height is ft (If needed, round to 1 decimal place.)
Mathematics
1 answer:
beks73 [17]3 years ago
3 0

Answer:

you could stand at 5.0 ft and still be completely in the shadow of the tree

Step-by-step explanation:

From the diagram attached below;

We consider;

\overline {BC} to be the height of the tree and \overline {DE} to be the height of how tall you could be and still be completely in the shadow of the tree.

∠D = ∠B = 90°

Also;

ΔEAD = ΔBAC   (similar triangles)

Therefore, their sides will also be proportional

i.e

\dfrac{\overline {DE}}{ \overline {BC}}= \dfrac{\overline{AD}}{ \overline{AC}}

\dfrac{x}{ 45}= \dfrac{225-220}{225}

\dfrac{x}{ 45}= \dfrac{25}{225}

By cross multiply

225x = 45 × 25

x = \dfrac{45 \times 25}{225}

x = \dfrac{1125}{225}

x = 5.0 ft

Therefore, you could stand at 5.0 ft and still be completely in the shadow of the tree

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The variable, y, varies directly with x. If y = 26 when x = 21,<br> what is y when x = 64?
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Answer:

dp/dt = 10⁻⁵p(2225 − 4.2381p)

Step-by-step explanation:

Since the function is

0 = ln p + 45.8177 − ln (2225 − 4.2381p) − 0.02225t

Differentiating the function implicitly with respect to time, we have

d0/dt = d[ln p + 45.8177 − ln (2225 − 4.2381p) − 0.02225t]/dt

d0/dt = d[ln p]/dt + d[45.8177]/dt − d[ln (2225 − 4.2381p)]/dt − d[0.02225t]/dt

0 = (1/p)dp/dt + 0 − (1/(2225 − 4.2381p)) × -4.2381 dp/dt − 0.02225

0 = (1/p)dp/dt + 4.2381 dp/dt/(2225 − 4.2381p)  − 0.02225

-(1/p)dp/dt - 4.2381 dp/dt/(2225 − 4.2381p)  = − 0.02225

(1/p)dp/dt + 4.2381 dp/dt/(2225 − 4.2381p)  =  0.02225

Factorizing out dp/dt from the left hand side, we have

[(1/p) + 4.2381/(2225 − 4.2381p)]dp/dt  =  0.02225

taking L.C.M of the left-hand-side and simplifying, we have

[((2225 − 4.2381p + 4.2381p)/p(2225 − 4.2381p)]dp/dt  =  0.02225

[2225/p(2225 − 4.2381p)]dp/dt  =  0.02225

dividing both sides by2225, we have

[1/p(2225 − 4.2381p)]dp/dt  =  0.02225/2225

[1/p(2225 − 4.2381p)]dp/dt  =  0.00001

[1/p(2225 − 4.2381p)]dp/dt  = 10⁻⁵

multiplying both sides by p(2225 − 4.2381p), we have

p(2225 − 4.2381p)[1/p(2225 − 4.2381p)]dp/dt  = 10⁻⁵p(2225 − 4.2381p)

So, dp/dt = 10⁻⁵p(2225 − 4.2381p)

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