If length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 $cm^{2}$ .

Given that length of rectangle is 8 cm, Breadth of rectangle is 4 cm,side of square is 3 cm,base of right angled triangle is 3 cm,height of triangle is 5 cm.

Area of figure=Area of rectangle+Area of square+Area of triangle

Area of rectangle=length*breadth

Area of square=Side*Side

Area of triangle=1/2 *Base*Height

Area of figure=8*4+3*3+1/2 *3*5

=32+9+1/2 *15

=41+15/2

=(82+15)/2

=97/2

=48.5 $cm^{2}$

Hence if length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 $cm^{2}$ .

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