Answer:
A
Step-by-step explanation:
Log poperties
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
Answer:
18
Step-by-step explanation:
18 over 1 is still 18. It shouldn't be a mixed number
Answer:
A. mean=14.29
median=16
B. IQR=10
C. option 3
D. 5.91
Step-by-step explanation:
mean=sum of values/number of values=10+20+4+13+21+16+16/7=14.29
median is achieved by arranging data in increasing order and then calculating the middle value
4 10 13 16 16 20 21
The mid value is 16 so the median=16
IQR=interquartile range=3rd quartile-1st quartile=Q3-Q1=20-10=10
As n/4=7/4 is not an integer so
Q1=(n/4+1)value=(7/4+1)=2.75=2nd value=10
Q3=(3n/4+1)value=6.25=6th value=20
Standard deviation=s=sqrt(∑(x-xbar)²/n-1)=sqrt(209.43/6)=5.91
