Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
The form would be
y = -4x + 2
Answer:
Step-by-step explanation:
If you can't solve it algebraically I suggest plot the points or lines and see if they meet the VTL (vertical line test).
Answer:
6.25 mins (6 minutes 15 seconds)
Step-by-step explanation:
96 tests = 2mins
300 tests = x mins
X = 2/96 x 300
X = 6.25 mins
He bought 4 books.
3.95m + 8.95b = 47.65
If he bought 3 magazines, m =3
(3.95)3 +8.95b = 47.65
11.85 + 8.95b =47.65
now we subtract 11.85 from both sides
8.95b = 35.80
we divide both sides by 8.95
b=4
Hugh bought 4 books.