15/7
5/2
2.54
2.7
That’s the order from least to greatest
Answer:
1. B. BD
2. C. 15
3. A. 2
Step-by-step explanation:
1. From the figure,
∠DAB = ∠DAC
Therefore, BD is the bisector of ∠ABC.
2. From the figure, IG = GH
3x = 5x - 10
10 = 5x - 3x
2x = 10
x = 5
So, GH = 5x - 10
= 5(5) - 10
= 25 - 10
= 15
Therefore, GH = 15.
3. From the figure,
∠DAB = ∠DAC
10y = 8y + 4
10y - 8y = 4
2y = 4
y = 2
Increment = 6% = 0.06
The explicit formula for the series is;
C(n) = C(n-1)(1.06), where n = nth month, C(n-1) = cost during previous month, C(n) = cost in month n
Applying the explicit formula;
Current cost = $150
2nd month cost = 150*1.06 = $159
3rd month cost = 159*1.06 = $168.54
The second option is correct.
Take the derivatives of each to get the tangent vectors:
Take the cross product of the tangent vectors to get a vector that is normal to both lines:
The two given lines intersect when 
:
that is, at the point (6, 4, 4).
The line perpendicular to both of the given lines through the origin is obtained by scaling the normal vector found earlier by 
; translate this line by adding the vector 
to get the line we want,
Answer:
(a) x² − 13x + 4
(b) x² − 26x + 153
Step-by-step explanation:
f(x) = x² + 3x − 2
a + ß = -3
aß = -2
(a) (x − a²) (x − ß²)
x² − (a² + ß²) x + a²ß²
x² − ((a + ß)² − 2aß) x + a²ß²
x² − ((-3)² − 2(-2)) x + (-2)²
x² − (9 + 4) x + 4
x² − 13x + 4
(b) (x − (a − ß)²) (x − (a + ß)²)
x² − ((a − ß)² + (a + ß)²) x + (a − ß)²(a + ß)²
x² − (a² − 2aß + ß² + a² + 2aß + ß²) x + (a² − 2aß + ß²)(a + ß)²
x² − (2a² + 2ß²) x + (a² − 2aß + ß²)(a + ß)²
x² − 2(a² + ß²) x + (a² − 2aß + ß²)(a + ß)²
x² − 2((a + ß)² − 2aß) x + ((a + ß)² − 4aß)(a + ß)²
x² − 2((-3)² − 2(-2)) x + ((-3)² − 4(-2))(-3)²
x² − 2(9 + 4) x + (9 + 8)(9)
x² − 26x + 153
