dP / dt = P / 10
We apply separable variables:
dP / P = dt / 10
We integrate both sides:
Ln (P) = t / 10 + C
We rewrite the equation:
Exp (Ln (P)) = Exp (t / 10 + C)
P = Exp (C) * Exp (t / 10)
P = C * Exp (t / 10)
We look for the constant using:
P (0) = 300
300 = C * Exp (0/10)
300 = C * 1
C = 300
We rewrite the equation:
P = 300 * Exp (t / 10)
After 40 hours we have:
P = 300 * Exp (40/10)
P = 16379.44501
Answer:
the population size after 40 hours is:
P = 16379
Answer:
44+50 =94 in²
Step-by-step explanation:
Trapezoid
A= 1/2h(b1+b2)
A= 1/2*4(7+15)
A=1/2*4(22)
A=44
Rectangle
A=l*w
A=5*10
A=50
44+50 =94 in²
The 6 measurements are 10.1, 10.02, 9.89, 10.05, 10.16, 10.21, and 10.11Mean -10.8333Sample size - 6Standard dev is 0.1Alpha is 1 – 0.90 Z (0.1) = 1.645So the computation would be:Mean ± Z* s/sqrt (n)= 10.0833 ± 1.645*0.1/sqrt(6)= 10.0833± 1.645*0.0408= 10.0833± 0.0672=10.0161, 10.1505 is the interval.90% confident that the iron rod’s true conductivity is between 10.0161 and 10.1504 microsiemens per centimeter.
Answer:
the hawk has flow 824.62 meters southwest of the mountain peak.
Step-by-step explanation:
In order to find the distance we need to use the Pythagoras theorem
d^2 = 800^2 + 200^2
d= 824.6 m
we can find the direction by using the eq for a tangent
he opposite side is 200 m and the adjacent side is 800m
tan theta = opposite / adjacent
theta = arc tan (800/200)
The hawk is at a distance of 824.6m flying at an angle 76 degrees NE of the mountain peak.
The final location will be southwest of the mountain peek.
a2+b2=c2
a = 200
b= 800
c = √(2002+8002) = 824.62
So the hawk has flow 824.62 meters southwest of the mountain peak.