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valina [46]
3 years ago
15

Let a and b be rational number

Mathematics
2 answers:
amid [387]3 years ago
5 0
Option a should be the anserw
Stels [109]3 years ago
3 0

Answer:

A)(Always)Rational

B)(Always)Rational

C)(Sometimes)Rational

This is because Square roots are generally irrational(like the \sqrt{2}) and the product and difference of rational numbers should always be rational!

Hope this helps!

Sorry, cannot explain more ... :(

P.S. Stay Safe!

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There are 5 candy canes for every 9 presents. How many candy canes are there when there are 108 presents
Ksju [112]

Answer:

When there are 108 presents, there are 60 candy canes

Step-by-step explanation:

candy canes : presents = 5:9

5/9 = x/108

cross multiply:

(5) (108) = 9x

540 = 9x, divide both sides by 9

x = 60

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1. According to New Jersey Transit, the 8:00 a.m. weekday train from Princeton to New York
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Does the graph represent a function?
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The area of a square game board is 144 sq. In. What's the length of the sides of the board?
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3 0
3 years ago
Read 2 more answers
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
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