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AnnZ [28]
4 years ago
6

What is the greatest possible whole number remainder if you divide any number by 23?

Mathematics
2 answers:
Goshia [24]4 years ago
7 0

trick question there's a infinite amount of numbers so there is no answer to that question

scientifically speaking of course


quester [9]4 years ago
6 0
The greatest possible whole number remainder is 22.

This is because if you have a remainder of 23, that would make it another whole group of 23. The greatest possible whole number remainder is always equal to the divisor subtracted by 1.

Hope this helps!
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Solve for t.
STALIN [3.7K]

Step-by-step explanation:

12gt^2=19\qquad\text{divide both sides by}\ 12g\\\\t^2=\dfrac{19}{12g}\to t=\sqrt{\dfrac{19}{12g}}

8 0
3 years ago
What does relationship mean in algebra/ math?
NikAS [45]

Answer:

A relation is a relationship between sets of values. In math, the relation is between the x-values and y-values of ordered pairs. The set of all x-values is called the domain, and the set of all y-values is called the range. ... The range consists of the y-values from each ordered pair.

7 0
3 years ago
What is the general equation of a cosine function with an amplitude of 3, a period of 4 pi, and a horizontal shift of negative p
liberstina [14]

The cosine function with the given characteristics is:

f(x) = 3*cos(x/2 - pi).

<h3>How to get the cosine function?</h3>

The general cosine function is:

f(x) = A*cos(kx + p)

Where A is the amplitude and p is the phase, then we know that:

A = 3

p = -pi

Then we have:

f(x) = 3*cos(kx - pi)

And the period is equal to 4pi, then we must have that:

k*(x + 4pi) - pi = k*x - pi + 2pi

k = 1/2

Then the function is:

f(x) = 3*cos(x/2 - pi).

If you want to learn more about cosine functions:

brainly.com/question/4372174

#SPJ4

3 0
2 years ago
Katie and Danielle recorded their resting heart rates each morning for ten days. The double dot plot shows their heart rates in
gladu [14]

Answer:

I think it is G

Step-by-step explanation:

So ya see, it really does peak at the given times.

8 0
3 years ago
Please help i dont get this at all
Tom [10]

Answer:

\frac{20y^{2} a^{2} }{41bx^{3} }

Step-by-step explanation:

1) Flip the second fraction and change the operation to multiplication:

\frac{5x^{2}y^{3}  }{2a^{5}b^{4}  } *  \frac{8a^{7}b^{3}  }{41x^{5}y  }

2) Cross cancel factors:

\frac{5y^{2}   }{2b  } *  \frac{8a^{2}  }{41x^{3}  }

3) Multiply:

\frac{40y^{2} a^{2} }{82bx^{3} }

4) Simplify:

\frac{20y^{2} a^{2} }{41bx^{3} }

4 0
3 years ago
Read 2 more answers
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