Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer:
Step-by-step explanation:
¿A qué se llamó feudalismo? ¿Dónde y cuándo se desarrolló?
Answer:
a. -3x = -2y
When x=6, y=9
Step-by-step explanation:
From the hanger, There are two sides
If x=triangle and y=square
First side has 1 triangle and 3 squares
It can be represented by
x+3y
Second side has 4 triangles and 1 square
It can be represented by
4x+y
Equate the first and second side
x+3y=4x+y
Collect like terms
x+3y-4x-y=0
-3x+2y=0
-3x=-2y
Find y when x=6
-3(6)=-2y
-18=-2y
Divide both sides by -2
-18/-2=-2y/-2
9=y
y=9
Answer:In the graph you need to use quradrant 4
Step-by-step explanation:
no need
