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tatuchka [14]
3 years ago
6

An alternating voltage of 240V,50HZ is connected across an impedance of (60-j100) Ω. Determine:

Mathematics
1 answer:
vivado [14]3 years ago
7 0

Answer:

justin beiber

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2 years ago
Is 2.0 a solution to the equation?<br><br> X-2y=0 , 2x-3y=1
Travka [436]
No, because (2,0) is a coordinate. x=2 and y=0. So just plug in the numbers where there's x or y with the appropriate number, (2 or 0). So in the first equation, x-2y=0, when you pug in the numbers, 2-2(0)=0, you know it's wrong because 2-0=0 isn't correct. So no. the point (2,0) is not a solution to the first equation. Now plug in the numbers for the second coordinate. You get 2(2)-3(0)=1. So 4-0=1. This is once again false no no. (2,0) satisfies neither equations. 
8 0
2 years ago
what number could be included in the data set 9,12,17,15,13 so the MEDIAN of the numbers in the set results in 14?
Georgia [21]

<em><u>Your answer is 12,17,15,13 if you take out the 9 your median will be 14.</u></em>


~*"AUBA14"*~

6 0
3 years ago
Read 2 more answers
Sam has nine yellow pencils in his desk 3/4 of his pencils are yellow how many pencils does Sam have in his desk
mrs_skeptik [129]

Answer:

12

Step-by-step explanation:

(# of pencils)x(3/4)=9

(# of pencils)x(0.75)=9

(# of pencils)=9/(0.75)=12

3 0
3 years ago
Assuming x &gt; 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
2 years ago
Read 2 more answers
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