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xenn [34]
3 years ago
14

The number of hours a group of contestants spent preparing for a quiz show are listed below. What is a frequency table that repr

esents the data?
60 25 86 56 45 48 90 75 30 67 90 36 80 15 32 65 61C
Mathematics
2 answers:
serious [3.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

Given in the number of hours a group of contestants spent preparing for a quiz

The list shows as follows:

60 25 86 56 45 48 90 75 30 67 90 36 80 15 32 65 61

In ascending order this becomes

x     15 25 30 32 36 45 48 56 60 61 65 67 75 80 86 90

F      1    1     1    1    1    1    1    1    1    1   1    1    1    1     1    2

Thus we have mode =90

All other entries have frequency 1 except 90

brilliants [131]3 years ago
5 0
<span>60 25 86 56 45 48 90 75 30 67 90 36 80 15 32 65 61

Hours                                      Frequency
  0 - 9                                            0
10-19  15                                      1
20-29  25                                      1
30-39  30, 36, 32                          3  
40-49  45, 48                                2
50-59  56                                      1 
60-69  60, 67, 65, 61                    4        
70-79  75                                      1
80-89  86, 80                                2
90-99  90, 90                                2</span>
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Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

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Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

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