Answer:
Two complex roots.
Step-by-step explanation:
F(x)=2x^4 +5x^3 - x^2 +6x-1
is a polynomial in x of degree 4.
Hence F(x) has 4 roots. There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.
Use remainder theorem to find the roots of the polynomial.
F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0
There is a change of sign in F from 0 to 1
Thus there is a real root between 0 and 1.
Similarly by trial and error let us find other real root.
F(-3) = -1 and F(-4) = 94
SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.
Other two roots are complex roots since no other place F changes its sign
Answer:
The original fraction is 13/27
Step-by-step explanation:
Let the fraction be x/y. This means that the numerator is x and the denominator is y.
One-fifth of the sum of the numerator and the denominator of a particular fraction is 8. This means that
1/5 (x+y) = 8
Cross multiplying with 5,
x+y = 5×8 = 40 - - - - - - - -1
If the numerator is subtracted from 22, the original fraction becomes 1/3. This means that
(22-x)/y = 1/3
Cross multiplying with y and 3,
3(22-x) = y×1
66-3x = y - - - - - -2
Substituting y = 66-3x into equation 1, it becomes
x + 66 - 3x = 40
x -3x = 40-66
-2x = -26
x = 26/2 = 13
y = 40 - x = 40 - 13
= 27
The original fraction is 13/27
Answer:
Step-by-step explanation:
C
1/5
Step-by-step explanation:
there is only one yellow bead 2 red and 3 green you add the red and green with a total of 5 getting a ratio of 1/5
