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mixer [17]
3 years ago
10

A couch and coffee table cost a total of $1080. The cost of the couch is two times the cost of the coffee table. Find the cost o

f each time.
Mathematics
1 answer:
Alborosie3 years ago
3 0

Answer:

$720

$360

Step-by-step explanation:

Let the cost of couch be A and that of coffee table be B

Given couch and coffee table cost $1080

That’s

A + B = $1080

Also, the cost of couch A is 2 times the cost of coffeee table B.

That’s

A = 2B

We now have two equations

A + B = 1080

A = 2B

Now ,substitute 2B for A in the first equation .

We have

A + B = 1080

2B + B = 1080

3B = 1080

Divide both sides by 3

3B/3 = 1080/3

B = 360

The coffee table cost $360

Remember A = 2B

Therefore

A = 2 x $360

A = $720

The couch cost $720 while the coffee table cost $360

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Evaluate using integration by parts ​
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Rather than carrying out IBP several times, let's establish a more general result. Let

I(n)=\displaystyle\int x^ne^x\,\mathrm dx

One round of IBP, setting

u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx

\mathrm dv=e^x\,\mathrm dx\implies v=e^x

gives

\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx

I(n)=x^ne^x-nI(n-1)

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I(5)=x^5e^x-5I(4)

I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)

I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)

I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)

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8 0
3 years ago
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