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Dima020 [189]
3 years ago
11

Hey! i’ll give brainliest thanks

Mathematics
1 answer:
lozanna [386]3 years ago
6 0
The second option:

He wanted to defeat the Persian Empire. But to do that, he needed to increase Macedonia's strength. Philip trained his army to fight like the Greek hoplites. Then, one by one, he took over the Greek city-states.
You might be interested in
145 300 610 1230
Vlad1618 [11]
Multiplying by 2 and then adding 10 145*2=290+10=300
300*2=600+10=610
610*2=1220 + 10=1230
x=2 y=10
x+y=12
5 0
3 years ago
A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books. What is the probability
Gnesinka [82]

Answer:

Probability that one of them is mathematics and other two are either physics or history books = 0.51

Step-by-step explanation:

Given - A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

To find - What is the probability one of them is mathematics and other two are either physics or history books ?

Solution -

Given that,

A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.

So,

Total number of books = 3 + 3 + 1 = 7

The student has to select 3 books

So, Total number of ways = ^{7} C_{3} = 35

So,

Probability that one of them is mathematics and other two are either physics or history books is -

= \frac{^{3} C_{1}. ^{4} C_{2}  }{^{7} C_{3}}

= \frac{(3)(6)}{35}

= \frac{18}{35}

= 0.51

⇒Probability that one of them is mathematics and other two are either physics or history books = 0.51

8 0
3 years ago
Please helppp will mark brainlyist with right answer
Len [333]
An angle bisector is a line or ray that divides an angle into two congruent angles
so
in this problem
m∠RST=m∠RSV+m∠VST
m∠RSV=m∠VST
hence
m∠RST=2*m∠RSV --------> equation 1
we have
m∠RST=(6x-24)
m∠RSV=(2x+8)
Substitute in the equation 1
6x-24=2*(2x+8)
6x-24=4x+16
6x-4x=16+24
2x=40
x=40/2
x=20 degrees
therefore
the value of x is 20 degrees
Tell me if I’m wrong
7 0
3 years ago
When dividing 250,000 by 100, the digits in the quotient move how many places to the right?
Zanzabum

When dividing 250,000 by 100, the digits in the quotient move by 2 places to the right.

<u>Step-by-Step explanation:</u>

Here we have , to find out that When dividing 250,000 by 100, the digits in the quotient move how many places to the right . Let's find out:

⇒  dividing 250,000 by 100

⇒  250,000 / 100

⇒  \frac{250000}{100}

⇒  \frac{2500(100)}{100}

⇒  2500

Initially we had 250,000 of 6 digits and now after dividing 250,000 by 100,  we have 2500 of 4 digits ! So , Number of places quotient shift to right is:

⇒ 6-4

⇒ 2

Therefore, When dividing 250,000 by 100, the digits in the quotient move by 2 places to the right.

6 0
3 years ago
A dj is preparing a playlist of 21 songs. how many different ways can the dj arrange the first six songs on the​ playlist?
kirill115 [55]
Answer: The are 39,070,080 different ways the DJ can play the first 6 songs.

We will use the Fundamental Counting Principle to find the answer. Simply determine the number of choices for each position and multiply.

For the first choice there are 21 choices. Then, the number is reduced by 1 each time.

So to get the answer, we have to multiply the numbers below:

21 x 20 x 19 x 18 x 17 x 16
6 0
3 years ago
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