Juan invested $100 in a savings account the earns 5% annually. The value, A, of the investment can be calculated using the equat
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Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation to
.
Further explanation:
Maricella begin by adding on the left side of the equation and
on the right side of the equation
.
The value added on the left is equal to zero so it does not change the equation but the value added on the right is 2, a non-zero digit so it changes the equation as shown below.
Therefore, the strategy used by Maricella will change the equation and so the solution of the equation will be incorrect.
One way of solving such a linear equation is by adding or subtracting the required value on each side of the equation. and then simplifying the further equation.
Similarly, the other way to solve any linear equation is by separating the variable terms on one side of the equation and constant terms on the other side of the equation.
After this simplify the linear equation to obtain the solution of the equation for .
Whereas Maricella’s strategy fails to solve the equation since the values added and subtracted in the equation changes the original equation completely.
Learn more:
1. Linear equation application brainly.com/question/2479097
2. To solve one variable linear equation brainly.com/question/1682776
3. Binomial and trinomial expression brainly.com/question/1394854
Answer details
Grade: Middle school
Subject: Mathematics
Chapter: Linear equation
Keywords: equation, linear equation, Maricella, right side, left side, strategy, solve for , adding, subtracting, variable, constant, solution of the equation, value, original equation, variable terms, constant terms.
Problem 4
<h3>Answer:</h3>------------------
Work Shown:
The left line goes through (-2,0) and (0,4)
The slope of this line is
m = (y2-y1)/(x2-x1)
m = (4-0)/(0-(-2))
m = (4-0)/(0+2)
m = 4/2
m = 2
The y intercept is b = 4
Since m = 2 and b = 4, this means y = mx+b turns into y = 2x+4. This portion is only done when x < 1. Note the open circle at the endpoint of this portion. So we do not include x = 1 as part of this piece.
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The line on the right side goes through (1,-2) and (2,-1)
Slope
m = (y2-y1)/(x2-x1)
m = (-1-(-2))/(2-1)
m = (-1+2)/(2-1)
m = 1/1
m = 1
The y intercept is b = -3. You can see this if you extend the line until it crosses the y axis.
Alternatively, plug in (x,y) = (1,-2) and m = 1 into y = mx+b to find that b = -3
So y = mx+b turns into y = 1x+(-3) or just y = x-3
We combine both parts to end up with
This is only graphed when (note the closed or filled in circle for the endpoint of this portion).
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Problem 5
Answer:
<h3>------------------
Work Shown:
y = |x| .... parent function
y = |x+3| ... shift 3 units to the left
y = (1/2)*|x+3| .... vertically compress by factor of 1/2
f(x) = (1/2)*|x+3|
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Break that down into a piecewise function
when x < -3, then y = -(1/2)(x+3)
when , then y = (1/2)(x+3)
I'm using the rule that y = |x| turns into y = -x when x < 0 and y = x when
So that is how we get as the piecewise function.