So we know that:
City A is -96ft in elevation
City C is -24ft in elevation
City D is (1/4C)ft in elevation.
So, knowing this we can make an equation: 1/4•-24/1=-24/4=-6
So from that, we get the result of City D being -6ft in elevation, or 6ft below sea level.
Answer:
Mean= $21.5067
Median = $15.8
Standard deviation= $19.02
Coefficient of skewness= $0.8991
Step-by-step explanation:
Mean =( $4.0 +$6.0 +$7.4+ $10.6 +$12.5+ $13.6+ $15.4+ $15.8 +$16.8
+$17.4+ $19.1 +$22.3+ $37.1 +$43.2 +$81.4)/15
Mean =$ 322.6/15
Mean= $21.5067
Median= middle number
Median = $15.8
Variance=( ($4.0-.$21.5)²+( $6.0. -.$21.5)²+( $7.4 -.$21.5)²+( $10.6 -.$21.5)²+( $12.5 -.$21.5)²+( $13.6. -.$21.5)²+ ($15.4 -.$21.5)²+( $15.8 -.$21.5)²+ ( $16.8 -.$21.5)²+ ($17.4-.$21.5)² +($19.1 -.$21.5)²+ ($22.3 -.$21.5)²+ ($37.1 -.$21.5)²+ ($43.2-.$21.5)²+( $81.4-.$21.5)²)/15
Variance=$ 5424.79/15
Variance=$ 361.65
Standard deviation= √ variance
Standard deviation= √361.65
Standard deviation= $19.02
Coefficient of skewness
=3( mean-median)/standard deviation
= 3(21.5-15.8)/19.02
= 3(5.7)/19.02
= 17.1/19.02
Coefficient of skewness= 0.8991
The rise & run for ΔABC is 1 and 3.
The slope is 1/3 because it is rise over run.
For ΔDFA, the rise and run is 2 and 6.
2/6 is equal to 1/3, so the slope is constant.
Hope this helps!
I think the answer is (3,3) I’m sorry if it’s wrong
