Let the event 'has cancer' be C, and the event 'works for Ajax' be A.
P(C) = 0.0019. P(A) = 0.28
The events A and C are independent if P(C|A) = P(C).
P(C|A) = 0.0019 = P(C).
Therefore the answer is YES.
1) Given: ds / dt = 3t^2 / 2s
2) Separate variables: 2s ds = 3t^2 dt
3) Integrate both sides:
∫ 2s ds = ∫ 3t^2 dt
s^2 + constant = t^3 + constant
=> s^2 = t^3 + constant
=> s = √ (t^3 + constant)
Answer: option B.
Answer:
170569
Step-by-step explanation:
Hi, check the comment. It is the answer. I wrote my own comment and rated myself 1.0 for no reason lol!! (Oh mah gawd I was joking this is not the answer, do NOT take this as your answer!
Answer:
Option A.
Step-by-step explanation:
In the given graph there are four intervals in which we have to find the nature of function.
1). In the interval (-∞, -0.7)
f(x) < 0
Because for every value of x, value of the function is negative.
2). In the interval (-0.7, 0.76)
f(x) > 0
For each value of x, value of the function is greater than 0.
3). In the interval (0.76, 2.5)
f(x) < 0
Because in this interval value of the function is negative.
4). Interval (2.5, ∞)
f(x) > 0
Because value of the function for every value of x, is greater than 0.
When we compile all four properties Option A. comes out to be the right option.
