Answer:
Rhombus
Step-by-step explanation:
I think so, probably.
Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
1. Method 1: By Listing MultiplesList out all multiples of each denominator, and find the first common one.
2: 2 , 4
4: 4
Therefore, the LCD is 4
Method 2: By Prime FactorsList all prime factors of each denominator, and find the union of these primes.
Therefore, the LCD is <span>2 x 2 = 4
</span>
2. <span>Make the denominators the same as the LCD
</span>
<span>
3. </span><span>Simplify. Denominators are now the same.
</span>
4. Join the denominators
5. <span>Simplify
</span>
<span>
Done! :) </span><span>Decimal Form: -0.25</span>
Try this solution:
for the circle A: circumference=6π, area=9π
for the circle B: circumference=12π, area=36π
PS. formula for circumference is 'L=2πr', for area is 'S=πr²'.
9514 1404 393
Answer:
- one: x+3 = 2x
- none: x+3 = x
- infinite: x+3 = x+3
Step-by-step explanation:
A linear equation with variable terms on opposite sides of the equal sign will have one solution when the coefficients of those variables are different.
x+3 = 2x . . . . has one solution (x=3)
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There will be no solution if the variable terms on opposite sides of the equal sign have the same coefficient, but the constants are different. Such an equation can be reduced to 0 = 1, which cannot be made true by any value of the variable.
x +3 = x . . . . has no solutions
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There will be an infinite number of solutions if the left side of the equal sign is the same as the right side. Every value of the variable will satisfy the equation.
x +3 = x +3 . . . . has infinite solutions
