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Sveta_85 [38]
4 years ago
11

Which represents an exterior angle of triangle ABF

Mathematics
2 answers:
mr Goodwill [35]4 years ago
7 0
The correct answer is CAB
andreyandreev [35.5K]4 years ago
3 0

Answer:BAD AFE CAD CAB

Step-by-step explanation:

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Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con
monitta

Let f(x)=e^{-1/x}. Then f'(x)=\frac1{x^2}e^{-1/x}>0 for all x\ge2, so f is strictly increasing. As x\to\infty, e^{-1/x}\to e^0=1, so f is bounded above by 1. This is to say,

e^{-1/x}

and the integral of \frac1{x^2} converges over the same domain, so this integral must also converge by comparison.

We have, by setting y=-\frac1x,

\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}

8 0
3 years ago
What is each product? For 5/10•10/3
Naily [24]
10 cancels out so its 5/3 :) Rate Me plz <span />
7 0
3 years ago
Please help me with this :)))))<br> If
jonny [76]

Answer:

c) x = 20, angle COD = 70 °

Step-by-step explanation:

(x+50)° + 90° +20° = 180°

x + 160° = 180°

x = 180°- 160°

x = 20

Angle COD = (x+50)° = (20 +50)° = 70°

Hope this helps

6 0
2 years ago
PLEASE HELP!!! What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
Elan Coil [88]

Answer:

32°

Step-by-step explanation:

This is an equilateral triangle which means all three sides of the triangle is equal so is the angles.

Therefore the value of x is : 2x - 4 = 60° ➡ 2x = 64° ➡ x = 32°

3 0
4 years ago
Is about inequalities, I know the rule of flipping the sign if you multiply or divide by a negative numbers but a few examples c
Westkost [7]

Answer:

do not flip the sign

Step-by-step explanation:

you only flip when you divide with negative number

however, for you to get the intercepts, you assumed

for y =0

5x +2(0)<14

5x<14

x<14/5<2.8

and also

x=0

5(0)+2y<14

2y<14

y<14/2

y<7

this assumption is because at interception, either x or y will be at origin

3 0
3 years ago
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