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Anastaziya [24]
4 years ago
7

In a science class students learn that friction is the resistance to motion when two objects rub together the students decide to

desing an expirement at home to compare friction on a dry and icy surfaces which question is most beneficial for this type of investigastion
Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
5 0
Which surface has the most friction?
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7. Marco is making beaded bracelets. Each
stiks02 [169]

One way to find the least common multiple of two numbers is to first list the prime factors of each number.

8 = 2 x 2 x 2

Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

2: three occurrences

3: one occurrence

So, our LCM should be

2 x 2 x 2 x 3 = 24.

So, Marco can buy, at the very least, 24 beads of each color to have equal colors of beads.

4 0
3 years ago
For each part below, use the figure to fill in the blank.
jenyasd209 [6]

Answer:

Step-by-step explanation:

5 0
3 years ago
1.Which example would be likely to give a valid conclusion?
storchak [24]

Answer:

1: C, ten from each class

2: 27

3: the numbers are counted incorrectly.

4: 5.5 hours

5: 6 hours

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Describe what a positive and negative residual looks like on a graph?
LUCKY_DIMON [66]

Answer:

positive ones are above the graph, and negative ones are below. It's because of the linear transgression and solvent

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
What is the missing step in the given proof? Help me out with my math homework please!
kari74 [83]

Answer: The missing step is,

m∠OCP ≅ m∠ABC because corresponding angles made by the same transversal on the parallel lines are congruent.

Step-by-step explanation:

Given : AC \parallel BD, AB \parallel CD

And, AC \perp CD

We have to Prove : Angle PCQ is complementary to  angle ABC

⇒ m\angle PCQ + m\angle ABC = 90^{\circ}

Proof:  Since, AC \perp CD

⇒  m\angle OCQ = 90^{\circ}

But,  m\angle OCQ = m\angle OCP +m\angle PCQ ( By angle addition postulate )

⇒  m\angle OCP +m\angle PCQ = 90^{\circ} ( By transitive property of equality )

Since, AC \parallel BD,

⇒ \angle OCP\cong \angle ABC ( corresponding angles made by the same transversal are congruent)

⇒  m\angle OCP = m\angle ABC ( By the definition of congruent angles )

This leads,

m\angle ABC +m\angle PCQ = 90^{\circ}  ( by the transitive property of equality )

Thus, by the definition of complementary angles,

Angle PCQ is complementary to  angle ABC

Hence proved.

5 0
3 years ago
Read 2 more answers
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