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AlexFokin [52]
3 years ago
15

Emma's curtain company is making curtains for a local hotel. She wants each curtain to be 24 inches long. At the fabric store, f

abric is sold by the foot. If Emma's curtain company wants to make 68 curtains, how many feet of fabric will she need? 1 inch = 1 12 foot
Mathematics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

136 feet

Step-by-step explanation:

Each curtain needs to be 24 inches long and we know 1 feet = 12 feet.

So 24 inches = 12*2 = 1*2 = 2 feet.

Each curtain is 2 ft.

So 68 curtains would be  68 * 2 = 136 feet.

Hence, 136 feet of fabric will be needed.

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Answer:

The objective function is P(x,y) = 55x + 95y

P(600, 1400) is $166000

P(600, 1700) is $194500

P(1500, 1700) is $244000

P(1200, 800) is $142000

P(1500, 800) is $158500

They need to sell 1500 of the basic models  and 1700 of the advanced models to make the maximum profit

Step-by-step explanation:

Let us solve the question

∵ x denotes the number of  basic models

∵ y is the number of advanced models

∵ They will make $55 on each basic model

∵ They will make $95 on each advanced model

→ The profit is the total amount of money-making on them

∴ Profit = 55(x) + 95(y)

∴ Profit = 55x + 95y

∴ The objective function is P(x,y) = 55x + 95y

Let us test the vertices on the objective function

∵ The vertices are (600, 1400), (600, 1700), (1500, 1700), (1200, 800),

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→ substitute each vertex in the objective function

∵ x = 600 and y = 1400

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∴ P(600, 1700) = $194500

∵ x = 1500 and y = 1700

∴ P(1500, 1700) = 55(1500) + 95(1700) = 244000

∴ P(1500, 1700) = $244000

∵ x = 1200 and y = 800

∴ P(1200, 800) = 55(1200) + 95(800) = 142000

∴ P(1200, 800) = $142000

∵ x = 1500 and y = 800

∴ P(1500, 800) = 55(1500) + 95(800) = 158500

∴ P(1500, 800) = $158500

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→ That means the maximum profit will be with vertex (1500, 1700)

∴ They need to sell 1500 of the basic models  and 1700 of the

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Substituting the known values,

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Multiplying this area by 4 will give us an answer of 72 in².


Then, we also calculate for the area of the square base.
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