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lesantik [10]
3 years ago
6

I got so confused with this math because since it’s Halloween my teacher nearly didn’t teach us

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
To answer this question, I need to know how much of each fruit Adrian bought
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$ 0.79 x 3.7
Troyanec [42]
$0.79
 x 3.7
---------
   553
+2370
---------
  2.923----> move the decimal three times to the left because that is how many spaces you have to the right on the actual equation until the next decimal.

The product of 0.79x 3.7 is 2.923. And, the decimal was moved three times to the right of the equation because of the number of spaces until the next decimal which then allows you to move the decimal three times to the left on the product. 

6 0
3 years ago
Carl deposited $5,142 into a savings account 20 years ago. The account has an interest rate of 3.8% and the balance is currently
Aleksandr [31]
Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.

If compounded annually, total = <span> <span> <span> 10,841.24 </span> </span> </span>
If compounded quarterly, total = <span> <span> <span> 10,955.64 </span>
</span></span><span>If compounded monthly, total = </span> <span> <span> <span> 10,981.82 </span> </span> </span>
If compounded daily, total = <span> <span> <span> 10,994.58 </span> </span> </span>
Therefore the answer is "A", daily.

Source:
http://www.1728.org/compint3.htm


<span> </span><span><span> </span> </span>

3 0
4 years ago
How do you multiply integers
Bumek [7]
5 times 4 equals 20. that's how
8 0
4 years ago
Read 2 more answers
If you have 60 and get 45 as discount how much the percentage
WINSTONCH [101]
Let x% be the percentage
60×(1-x%)=45
1-x%=0.75
x=25%
7 0
4 years ago
Find the sum of the geometric series.<br><br> a <br> b <br> c <br> d
Musya8 [376]

Answer:

B. 4\sqrt{3}-6

Step-by-step explanation:

We have,

The first term of the series, a=\sqrt{3}.

The common difference is given by, r=\frac{\frac{-3}{2}}{\sqrt{3}} i.e. r=\frac{-\sqrt{3}}{2}.

Since, the given series is an infinite series, then,

Sum of an infinite series = \frac{a}{1-r}

i.e. Sum the series = \frac{\sqrt{3}}{1+\frac{\sqrt{3}}{2}}

i.e. Sum the series = \frac{2\sqrt{3}}{2+\sqrt{3}}

i.e. Sum the series = \frac{2\sqrt{3}}{2+\sqrt{3}}\times \frac{2-\sqrt{3}}{2-\sqrt{3}}

i.e. Sum the series = \frac{2\sqrt{3}\times (2-\sqrt{3})}{4-3}

i.e. Sum the series = 4\sqrt{3}-6

Thus, the sum of the series is 4\sqrt{3}-6.

8 0
3 years ago
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