The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
images are:
W'(-5,0)
X'(0,-9)
Y'(-9,-6)
Z'(-6,-2)
Step-by-step explanation:
use formula p(x,y)=p'(y,-x)
Answer:
Bob at the store
Step-by-step explanation:
Bob is at a store and wants to buy a banana, last time he checked it costed 2/6 of a dollar. Now it costs 3/4 times more.
Answer:
a = 16
Step-by-step explanation:
6 = a/4 + 2
4 = a/4 Subtract 2 from both sides
16 = a Multiply 4 to both sides
Are you trying to simplify? if so, the answer is 13u/6
