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2 years ago

PLEASE HELP GIVING BRAINLY!!! (if you could at least help me with 1 or even both I’ll give brainly!!)

Mathematics

1 answer:

Fiesta28 [93]2 years ago

7 0

Answer:

1. 4

Step-by-step explanation:

24 - 20, if you add the the square then the rectangle, then subtract

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I am a 2 digit number.

AlexFokin [52]

Answer:

Step-by-step explanation:

6+5=11

5 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

6 0

2 years ago

Rewrite the numbers from least to greatest 0.33,-0.12,-0.127,0.2,45/10

Sonbull [250]

-0.127
-0.12
0.20
0.33
45/10
I think that is right

8 0

3 years ago

Read 2 more answers

If x = (7+4√3), then the value of x^2 + 1/x^2 is

Blizzard [7]

Answer:

194.

Step-by-step explanation:

x = (7+4√3)

x^2 = x = (7+4√3)^2

= 49 + 48 + 56√3

= 97 + 56√3

x^2 + 1/x^2 = 97 + 56√3 + 1/(97 + 56√3)

= 194.

5 0

2 years ago

At a farmers' market Saturday, 5/8 of the vegetables sold were green. Of these, 3/4 were string beans. What fraction of the vege

Dennis_Churaev [7]

Answer: 15/32

Step-by-step explanation:

The data that we have is:

5/8 of the vegetable sold where green.

of theses 5/8, 3/4 were string beans.

Then the 3/4 is applied to the 5/8 of green vegetables.

Then the fraction (of the total number of vegetables) that were string beans was:

F = (3/4)*(5/8) = (3*5)/(4*8) = 15/32

3 0

3 years ago