Your rate of change would be 3/4 lb/week.
You could model this with a linear eq:
y = 8+ 3/4x
If 2-4=20 than x is equal to 12
Point-Slope Equation: y - y₁ = m(x - x₁) ; where (x₁, y₁) is the point and m is the slope
(x₁, y₁) = (4, 1700) and m = 200
y - 1700 = 200(x - 4)
Answer: bottom left
Y= -7/5x + 4
To find -intercept/zero, substitute
Multiply both sides of the equation by
0= -7/5x +4
Move the variable to the left-hand side and change its sign
0= -7x +20
Divide both sides of the equation by
7x=20
20/7 = 2 6/7 = x 2.857
Answer:
The pythagorean identity that is correct is option B:
B. tan^2(theta)+1=sec^2(theta)
Step-by-step explanation:
The pythagorean identities are:
1.) sin^2(theta) + cos^2(theta) = 1
2.) tan^2(theta) + 1 = sec^2(theta)
3.) 1 + cot^2(theta) = csc^2(theta)
Then the pythagorean identity that is correct is option B:
B. tan^2(theta)+1=sec^2(theta)
