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podryga [215]
3 years ago
11

Please help me !!!

Mathematics
2 answers:
kati45 [8]3 years ago
5 0
23)~75r^2-48=3(25r^2-16)=3(5r-4)(5r+4)\\\\
24)~45x^2-5=5(9x^2-1)=5(3x-1)(3x+1)\\\\
25)~m^3n-mn^3=mn(m^2-n^2)=mn(m-n)(m+n)\\\\
26)~6a^3-24ab^2=6a(a^2-4b^2)=6a(a-2b)(a+2b)\\\\
27)~3x^2+15x-72=3(x^2+5x-24)=3(x-3)(x+8)\\\\
28)~2m^2-4m+2=2(m^2-2m+1)=2(m-1)^2\\\\
29)~x^3+9x^2-52x=x(x^2+9x-52)=x(x-4)(x+13)\\\\
30)~4y^3+4y^2-120y=4y(y^2+y-30)=4y(y-5)(y+6)
Dahasolnce [82]3 years ago
5 0
#23
Take out a GCF of 3(25x^2-16)
3(5x-4)(5x+4)
#24
Take out GCF of 5
5(9x^2-1)
5(3x-2)(3x+1)
#25
GCF mn(m^2-n^2)
mn(m-n)(m+n)
#26
6a(a-2b)(a+2b)
#27
3(x+8)(x-3)
#28
2(m-1)(m-1)
#29
x(x-4)(x+13)
#30
4y(y+6)(y-5)

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Step-by-step explanation:

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(a) In order to create an equation for an arithmetic sequence, you need to find the common difference(d) and the 0th term. You can find the common difference by finding the difference between two consecutive terms:

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