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UkoKoshka [18]
3 years ago
14

Use the order of operations and the digits 2, 4, 6, and 8 to create an expression with a value 2.

Mathematics
1 answer:
Fed [463]3 years ago
6 0

Answer:

8 +  {2}^{2}  - (4 + 6)

Step-by-step explanation:

We want use the order of operations and the digits 2, 4, 6, and 8 to create an expression with a value 2.

The expression is:

8 +  {2}^{2}  - (4 + 6)

The order of operations is PEDMAS

Deal with parenthesis first,

8 +  {2}^{2}  - 10

Next deal with exponent

8 + 4 - 10

No Division and Multiplication so skip to Addition.

12 - 10

Finally subtract to get:

2

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Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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2 years ago
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25 students
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SVETLANKA909090 [29]

Step-by-step explanation:

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✓(-4/42)+(2/30)

✓(-2/21)+(1/15)

✓(-2/21+1/15)

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How do you write 720,080 in expanded form with exponents
liraira [26]
The expanded form for that problem would be (7x10^5) + (2 × 10^4) + (8x10^1)
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