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UkoKoshka [18]
3 years ago
14

Use the order of operations and the digits 2, 4, 6, and 8 to create an expression with a value 2.

Mathematics
1 answer:
Fed [463]3 years ago
6 0

Answer:

8 +  {2}^{2}  - (4 + 6)

Step-by-step explanation:

We want use the order of operations and the digits 2, 4, 6, and 8 to create an expression with a value 2.

The expression is:

8 +  {2}^{2}  - (4 + 6)

The order of operations is PEDMAS

Deal with parenthesis first,

8 +  {2}^{2}  - 10

Next deal with exponent

8 + 4 - 10

No Division and Multiplication so skip to Addition.

12 - 10

Finally subtract to get:

2

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Answer:

12.6

Step-by-step explanation:

The answer is 12.6 and here is the explanation of using the Distributive Property. Because we are multiplying a whole number by a mixed number, we have to multiply the whole number by the whole number in the mixed number and then multiply the whole number by the fraction. In this case, we have 3 x 4 1/5. We multiply 3x4=12 first, and then we multiply 3x1/5 to get 0.6. 12+0.6=12.6. Hope it helps!

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Find the values of x and y.
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Which is a better deal: five tulips for $3.00 or seven tulips for $4.00?
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Read 2 more answers
Da<br> A<br> Solve the equation 2x^2+3=0
Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Solving quadratics

<u>Algebra II</u>

Imaginary root i

  • √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 3 on both sides:                        2x² = -3
  2. [Division Property of Equality] Divide 2 on both sides:                                  x² = -3/2
  3. [Equality Property] Square root both sides:                                                    x = ±√(-3/2)
  4. Simplify:                                                                                                             x = ±i(√6 / 2)
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3 years ago
Which statement is not always true?
Fed [463]
Statement #3: The product of two irrational numbers is not always irrational.

If you multiply √3 and 1/√3, both irrational numbers that are inverses of each other, you end up getting 1, which is rational.
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3 years ago
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