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user100 [1]
3 years ago
10

I need help plz answer as soon as possible

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

x = 7

Step-by-step explanation:

Let's join A & C . If points A ,B & C are collinear , then definitely B point's gonna lie on line segment AC .

So , AC = AB + BC

In the question , length of AC = 3x + 3 , length of AB = 2x - 1 ( or -1 + 2x)

& length of BC = 11.

We know that AC = AB + BC . So putting the given values here :-

3x+3 = 2x -1 + 11\\=>3x +3 = 2x+10\\

Solving this linear eqn. gives

3x + 3=2x+10\\=> 3x-2x=10-3\\=>x=7

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Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 ​ h, (, x, ), equals, start fraction, 1, divided
tiny-mole [99]

Answer:

\dfrac{47}{60} sq. units.

Step-by-step explanation:

The given function is

h(x)=\dfrac{1}{7-x}

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)

For given question,

Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)

Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)

Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)

Now,

Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)

Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}

Area=\dfrac{12+15+20}{60}

Area=\dfrac{47}{60}

Therefore, the required area is \dfrac{47}{60} sq. units.

5 0
3 years ago
A recently admitted class of graduate students at a large state university has a mean GRE verbal score of 650 with a standard de
hjlf

Answer:

The answer is below

Step-by-step explanation:

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