First you need to work out how much string is needed -
256 pieces needed x 40cm each:
256 x 40 = 10240cm
Then, convert to metres (100cm = 1m)
10240 / 100 = 102.4m
Then, you work out how many balls are needed:
30 can fit into 102.4 3 times with .41m to spare. So, you need three balls of string, PLUS another one to cover the 41cm
So to conclude: 4 balls of string are needed.
Answer:6x+6... not sure
Step-by-step explanation:
Sry if I’m wrong
Answer:
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Step-by-step explanation:
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If you just want to know what is the least common multiple of 20 and 15, it is 60. Usually, this is written as
lcm(20,15) = 60
g(x) = x - 3 = 0
g(x) = x = 3
f(x) = 2x^3 + x - 4
f(3) = 2(3)^3 + 3 - 4
f(3) = 2(27) - 1
f(3) = 54 - 1
f(3) = 53
The remainder when f(x) is divided by x - 3 is <u>53</u>.