A^2-b^2=(a+b)(a-b)
1: x^2-4=(x+2)(x-2)
2: (x+8)(x-8)
3: (x+10)(x-10)
4: (x+14)(x-14)
Answer:
Step-by-step explanation:
Answer:
D) Yes. The five trials are independent, have only two outcomes, and have the same P(success); n = 5, r = 2, p = 1/6.
Step-by-step explanation:
The Number of boxes = 6
Box containing a prize = 1
Probability of success, p = box containing a price / number of boxes = 1 /6
Number of trials = 5
Probability of success on exactly 2 trials, r = 2
Hence,
P(r = 2) = nCr * p^r * (1-p)^(n-r)
n = 5 ; r = 2 ; p = 1/6
Using a binomial probability calculator :
P(r = 2) = 0.1608
