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AlladinOne [14]
3 years ago
8

F= 9/5c + 32 solve for C​

Mathematics
1 answer:
Zolol [24]3 years ago
8 0
F I think so and thank you
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If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2
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If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width

Solution:

Let the length of rectangle=x

Width of rectangle=x/10

Perimeter is 2(Length+Width)

= 2(x+x/10)

Area of Rectangle= Length* Width=x*x/10

As, Perimeter=2(Area)

So,2(x+x/10)=2(x*x/10)

Multiplying the equation with 10, we get,

2(10x+x)=2x²

Adding Like terms, 10x+x=11x

2(11x)=2x^2

22x=2x²

2x²-22x=0

2x(x-11)=0

By Zero Product property, either x=0

or, x-11=0

or, x=11

So, Width=x/10=11/10=1.1

Checking:

So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2

Area=Length*Width=11*1.1=12.1

Hence, Perimeter= 2 Area

As,24.2=2*12.1=24.2

So, Perimeter=2 Area

So, Answer:Length of Rectangle=11 units

Width of Rectangle=1.1 units

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The area in square feet of a rectangular field is x²-110x+3000. The​ width, in​ feet, is x−50. What is the​ length, in​ feet?
ioda

x-60 is the length. Multiply you get x2-110x=3000 this is a quadratic equation.

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Jose buys a drink and dinner at a local restaurant. The dinner was $9.89 and the drink was $1.99. Jose would like to leave a 15%
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