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Vsevolod [243]
3 years ago
10

The first step to solve the equation StartFraction x over 4 EndFraction minus three-fourths = 16 is shown below. StartFraction x

over 4 EndFraction minus three-fourths + three-fourths = 16 + three-fourths Which property was applied in this step?
Mathematics
1 answer:
artcher [175]3 years ago
5 0

Answer:

Addition property of equality

Step-by-step explanation:

The given expression is :

\dfrac{x}{4}-\dfrac{3}{4}=16

We need to find the first step to solve this expression.

For this, we add 3/4 to both sides of the equation i.e.

\dfrac{x}{4}-\dfrac{3}{4}+\dfrac{3}{4}=16+\dfrac{3}{4}\\\\\dfrac{x}{4}=16+\dfrac{3}{4}

So, we have used the addition property of equality.

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Answer:

Angle 3 is = to angle 2 because:

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Angle 7 & angle 2 are vertical angles, meaning they also have the same measure.

Therefore, if angle 7 is equal to angle 3, then angle 2 must also be equal to angle 3.

Hope this helps! Have a great day!

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Write the slope intercept form of the line parallel to 7x+y=5 that passes through the point (3,-2)
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Step-by-step explanation:

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3 years ago
Proof that :<br><img src="https://tex.z-dn.net/?f=%20%7Bsin%7D%5E%7B2%7D%20%5Ctheta%20%2B%20%20%7Bcos%7D%5E%7B2%7D%20%5C%3A%5Cth
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Answer:

Solution given:

Right angled triangle ABC is drawn where <C=\theta

we know that

\displaystyle Sin\theta=\frac{opposite}{hypotenuse} =\frac{AB}{AC}

\displaystyle Cos\theta=\frac{adjacent}{hypotenuse}=\frac{BC}{AC}

Now

left hand side

\displaystyle {sin}^{2} \theta + {cos}^{2} \:\theta

Substituting value

(\frac{AB}{AC})²+(\frac{BC}{AC})²

distributing power

\frac{AB²}{AC²}+\frac{BC²}{AC²}

Taking L.C.M

\displaystyle \frac{AB²+BC²}{AC²}....[I]

In ∆ABC By using Pythagoras law we get

\boxed{\green{\bold{Opposite²+adjacent²=hypotenuse²}}}

AB²+BC²=AC²

Substituting value of AB²+BC² in equation [I]

we get

\displaystyle \frac{AC²}{AC²}

=1

Right hand side

<h3><u>proved</u></h3>

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Answer:

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Step-by-step explanation:

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