If the width of the garden is w, then the maximum area available is a square, giving you w² as the dimensions. So:
w²=-w²+28w
2w²=28w
w=14
The perimeter is 14 x 4, or 56 feet
How many seed packets??? No idea
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Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
The answer is -1/16 or -0.0625, do you need to see work?
So,
53,879 rounded to the nearest hundred:
If the number in the tens place is greater than or equal to 5, then round up. If not, round down.
7 is greater than or equal to 5, so round up.
53,879 --> 53,900
Answer:
Step-by-step explanation:
False you must multiply the coefficient (numbers) and add the exponents.
